Unexpected edge being filleted

[bfedie518]

I apparently don't understand how the selectors work. I would expect the following two code snippets to fillet the same edges.

result = result.edges("(>Z and >X) or (<Y and |Z)").fillet(0.5)

and

result = result.edges(">Z and >X").fillet(0.5)
result = result.edges("<Y and |Z").fillet(0.5)

When using result = cq.Workplane().box(5, 5, 5), the first line behaves how I would expect:

The chained operations select an additional edge that doesn't fit with either set of filters:

Can someone explain how this is working? The selector portions of the documentation don't seem to explain this behavior.

[lorenzncode]

I could not reproduce it. Here is my result. I tested with both 2.7.0 and master (conda/pixi). Which version is this?

import cadquery as cq
from cadquery.vis import show

result1 = cq.Workplane().box(5, 5, 5)
result2 = result1.edges(">Z and >X").fillet(0.5).val().move(x=6)
result3 = result1.edges("<Y and |Z").fillet(0.5).val().move(x=2*6)
result4 = result1.edges("(>Z and >X) or (<Y and |Z)").fillet(0.5).val().move(x=3*6)


show([result1, result2, result3, result4], width=800, height=600)

[bfedie518]

I could not reproduce it. Here is my result. I tested with both 2.7.0 and master (conda/pixi). Which version is this?

import cadquery as cq
from cadquery.vis import show

result1 = cq.Workplane().box(5, 5, 5)
result2 = result1.edges(">Z and >X").fillet(0.5).val().move(x=6)
result3 = result1.edges("<Y and |Z").fillet(0.5).val().move(x=2*6)
result4 = result1.edges("(>Z and >X) or (<Y and |Z)").fillet(0.5).val().move(x=3*6)

show([result1, result2, result3, result4], width=800, height=600)

You're doing a separate operation for each cube. My second example is equivalent to chaining two fillets on the same cube.
result = cq.Workplane().box(5, 5, 5).edges(">Z and >X").fillet(0.5).edges("<Y and |Z").fillet(0.5)

In context I'm trying to fillet a part, make a copy of that part, then add some more fillets only to the copy.

base = cq.Workplane().box(5, 5, 5)
result = base.edges(">Z and >X").fillet(0.5)
result2 = result.edges("<Y and |Z").fillet(0.5).val().move(x=6)
show([result, result2])

Version 2.7.0 downloaded via pip

[lorenzncode]

Your selector is correct. So this is the CAD kernel fillet behavior for this scenario as far as I know. Another example.

import cadquery as cq
from cadquery.fig import Figure 

base = cq.Workplane().box(5, 5, 5)
result1 = base.edges("<Y and |Z").fillet(0.5)
selected_edge = result1.edges(">Z and >X")
result2 = result1.edges(">Z and >X").fillet(0.5)

fig = Figure()
fig.clear()
fig.show(selected_edge, name="selected_edge")
fig.show(result1, name="result1")
fig.show(result2, name="result2")

ipython
run <file.py>

[bfedie518]

Interesting. Is there a way to get the behavior that I actually want? Anything that would have the same effect as the Sketch reset() function?

[adam-urbanczyk]

This is not a selection issue (try with a chmafer) but rather a OCCT kernel issue.

I can only make it work when doing the fillet in on go (NB: using unreleased selection combination operator | from #2038 ):

from cadquery.func import *
from cadquery.fig import *

base = box(5, 5, 5,)
res = fillet(base, base.faces('>X').edge('<Y') | base.faces('>Z').edge('>X'), 0.5)

clear()
show(res)

[bfedie518]

Ah, I understand now. Is there any chance it's an issue with how CadQuery interacts with OCCT? Or is it for sure a bug with the kernel itself?
If it's the latter this issue can probably be closed. An issue will have to be opened on the Open Cascade Github instead.