Create README - LeetHub

Author: JanaSabuj

word-ladder-ii/README.md

@@ -0,0 +1,40 @@
+<h2>126. Word Ladder II</h2><h3>Hard</h3><hr><div><p>A <strong>transformation sequence</strong> from word <code>beginWord</code> to word <code>endWord</code> using a dictionary <code>wordList</code> is a sequence of words <code>beginWord -&gt; s<sub>1</sub> -&gt; s<sub>2</sub> -&gt; ... -&gt; s<sub>k</sub></code> such that:</p>
+
+<ul>
+	<li>Every adjacent pair of words differs by a single letter.</li>
+	<li>Every <code>s<sub>i</sub></code> for <code>1 &lt;= i &lt;= k</code> is in <code>wordList</code>. Note that <code>beginWord</code> does not need to be in <code>wordList</code>.</li>
+	<li><code>s<sub>k</sub> == endWord</code></li>
+</ul>
+
+<p>Given two words, <code>beginWord</code> and <code>endWord</code>, and a dictionary <code>wordList</code>, return <em>all the <strong>shortest transformation sequences</strong> from</em> <code>beginWord</code> <em>to</em> <code>endWord</code><em>, or an empty list if no such sequence exists. Each sequence should be returned as a list of the words </em><code>[beginWord, s<sub>1</sub>, s<sub>2</sub>, ..., s<sub>k</sub>]</code>.</p>
+
+<p>&nbsp;</p>
+<p><strong>Example 1:</strong></p>
+
+<pre><strong>Input:</strong> beginWord = "hit", endWord = "cog", wordList = ["hot","dot","dog","lot","log","cog"]
+<strong>Output:</strong> [["hit","hot","dot","dog","cog"],["hit","hot","lot","log","cog"]]
+<strong>Explanation:</strong>&nbsp;There are 2 shortest transformation sequences:
+"hit" -&gt; "hot" -&gt; "dot" -&gt; "dog" -&gt; "cog"
+"hit" -&gt; "hot" -&gt; "lot" -&gt; "log" -&gt; "cog"
+</pre>
+
+<p><strong>Example 2:</strong></p>
+
+<pre><strong>Input:</strong> beginWord = "hit", endWord = "cog", wordList = ["hot","dot","dog","lot","log"]
+<strong>Output:</strong> []
+<strong>Explanation:</strong> The endWord "cog" is not in wordList, therefore there is no valid transformation sequence.
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= beginWord.length &lt;= 5</code></li>
+	<li><code>endWord.length == beginWord.length</code></li>
+	<li><code>1 &lt;= wordList.length &lt;= 1000</code></li>
+	<li><code>wordList[i].length == beginWord.length</code></li>
+	<li><code>beginWord</code>, <code>endWord</code>, and <code>wordList[i]</code> consist of lowercase English letters.</li>
+	<li><code>beginWord != endWord</code></li>
+	<li>All the words in <code>wordList</code> are <strong>unique</strong>.</li>
+</ul>
+</div>