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Author: JanaSabuj

word-search/README.md

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+<h2>79. Word Search</h2><h3>Medium</h3><hr><div><p>Given an <code>m x n</code> grid of characters <code>board</code> and a string <code>word</code>, return <code>true</code> <em>if</em> <code>word</code> <em>exists in the grid</em>.</p>
+
+<p>The word can be constructed from letters of sequentially adjacent cells, where adjacent cells are horizontally or vertically neighboring. The same letter cell may not be used more than once.</p>
+
+<p>&nbsp;</p>
+<p><strong>Example 1:</strong></p>
+<img alt="" src="https://assets.leetcode.com/uploads/2020/11/04/word2.jpg" style="width: 322px; height: 242px;">
+<pre><strong>Input:</strong> board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "ABCCED"
+<strong>Output:</strong> true
+</pre>
+
+<p><strong>Example 2:</strong></p>
+<img alt="" src="https://assets.leetcode.com/uploads/2020/11/04/word-1.jpg" style="width: 322px; height: 242px;">
+<pre><strong>Input:</strong> board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "SEE"
+<strong>Output:</strong> true
+</pre>
+
+<p><strong>Example 3:</strong></p>
+<img alt="" src="https://assets.leetcode.com/uploads/2020/10/15/word3.jpg" style="width: 322px; height: 242px;">
+<pre><strong>Input:</strong> board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "ABCB"
+<strong>Output:</strong> false
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>m == board.length</code></li>
+	<li><code>n = board[i].length</code></li>
+	<li><code>1 &lt;= m, n &lt;= 6</code></li>
+	<li><code>1 &lt;= word.length &lt;= 15</code></li>
+	<li><code>board</code> and <code>word</code> consists of only lowercase and uppercase English letters.</li>
+</ul>
+
+<p>&nbsp;</p>
+<p><strong>Follow up:</strong> Could you use search pruning to make your solution faster with a larger <code>board</code>?</p>
+</div>