1333-filter-restaurants-by-vegan-friendly-price-and-distance.js

/**
 * 1333. Filter Restaurants by Vegan-Friendly, Price and Distance
 * https://leetcode.com/problems/filter-restaurants-by-vegan-friendly-price-and-distance/
 * Difficulty: Medium
 *
 * Given the array restaurants where  restaurants[i] = [idi, ratingi, veganFriendlyi, pricei, distancei].
 * You have to filter the restaurants using three filters.
 *
 * The veganFriendly filter will be either true (meaning you should only include restaurants with
 * veganFriendlyi set to true) or false (meaning you can include any restaurant). In addition, you
 * have the filters maxPrice and maxDistance which are the maximum value for price and distance of
 * restaurants you should consider respectively.
 *
 * Return the array of restaurant IDs after filtering, ordered by rating from highest to lowest.
 * For restaurants with the same rating, order them by id from highest to lowest. For simplicity
 * veganFriendlyi and veganFriendly take value 1 when it is true, and 0 when it is false.
 */

/**
 * @param {number[][]} restaurants
 * @param {number} veganFriendly
 * @param {number} maxPrice
 * @param {number} maxDistance
 * @return {number[]}
 */
var filterRestaurants = function(restaurants, veganFriendly, maxPrice, maxDistance) {
  return restaurants.filter(([,, v, p, d]) => v >= veganFriendly && p <= maxPrice && d <= maxDistance)
    .sort((a, b) => a[1] === b[1] ? b[0] - a[0] : b[1] - a[1])
    .map(r => r[0]);
};