Formatter

Author: ksw2000

Array/01-動態宣告二維陣列.c

@@ -3,7 +3,7 @@
 
 // How to simply allocate 2D array on runtime (in heap)?
 
-int** allocate2D(int rows, int cols){
+int** allocate2D(int rows, int cols) {
     // allocate memory for rows
     int** array2D = array2D = malloc(sizeof(int*) * rows);
 
@@ -15,16 +15,16 @@ int** allocate2D(int rows, int cols){
     return array2D;
 }
 
-void free2D(int** array2D, int rows){
+void free2D(int** array2D, int rows) {
     int i;
-    for(i=0; i<rows; i++){
+    for (i = 0; i < rows; i++) {
         free(array2D[i]);
     }
     free(array2D);
 }
 
 int main() {
-    int rows = 9; 
+    int rows = 9;
     int cols = 5;
     int** array2D = allocate2D(rows, cols);
 

Array/02-動態宣告連續二維陣列.c

@@ -2,16 +2,15 @@
 #include <stdlib.h>
 
 // Write a function called malloc2D() which allocates a 2d array.
-// Minimize the number of calls to malloc() and make sure te memory is accessible
-// by the notation array[i][j]
-// Try allocate this as a contiguous block of memory, that space can be released
-// by a single free() call.
+// Minimize the number of calls to malloc() and make sure te memory is
+// accessible by the notation array[i][j] Try allocate this as a contiguous
+// block of memory, that space can be released by a single free() call.
 
 int** allocate2D(int rows, int cols) {
     size_t overhead = sizeof(int*) * rows;
     void** array = malloc(overhead + sizeof(int) * rows * cols);
-    int i = 0;
-    for (; i < rows; i++) {
+    int i;
+    for (i = 0; i < rows; i++) {
         array[i] = array + overhead + i * cols;
     }
     return (int**)array;