[BUG][PYTHON] Getting a file response in OpenAPI v3 / python

[charlesfleche]

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• Have you provided a full/minimal spec to reproduce the issue?
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Description

I'm trying to define a file response:. In the generated python code, I see that for a file type, the function __deserialize_file is called, and it's exactly what I want: it save the HTTP response body as a temporary file on the filesystem and returns its path.

The problem is that the response_type file is never defined, it's always a bytearray.

How can I tell the python wrapper generator to write a file response to a temporary file (calling __deserialize_path) ?

openapi-generator version

7.11.0

OpenAPI declaration file content or url

openapi: 3.1.1
info:
  description: repro
  title: repro
  version: '1.0.0'
paths:
  /content:
    get:
      description: Returns data for all given object ids
      responses:
        '200':
          content:
            application/png:
              schema:
                type: string
                format: binary
          description: The file response

Generation Details

pip install openapi-generator-cli[jdk4py]
openapi-generator-cli.exe generate -i .\repro.yml -g python -o src

Steps to reproduce

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