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Release 0.4.0 (#516)
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‎CHANGELOG.md‎

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This project adheres to [Semantic Versioning](http://semver.org/).
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### Types of changes:
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* **Added** for new features.
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* **Changed** for changes in existing functionality.
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* **Fixed** for any bug fixes.
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* **Removed** for now removed features.
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## [0.3.1] - [ 2025-01-31 ]
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## [ 0.4.0 ] - [ 2025-04-28 ]
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### Added
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- Assembly declaration
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- `Rn` unitary instruction
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- `SWAP2CZDecomposer` decomposer pass
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- `CZDecomposer` decomposer pass
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- `ShortestPathRouter` router pass
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- `RandomMapper` mapper pass
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- `AStarRouter` router pass
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### Changed
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- libQASM 1.1.0 integrated (updated from 0.6.9)
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- Refactor: removed generators
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- Changed the `RoutingChecker` pass to a `RoutingValidator` pass
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- Changed use of `native` to `primitive`, e.g. `NativeGateValidator` is now `PrimitiveGateValidator`
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- Compilation passes accept `kwargs` as input
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## [ 0.3.1 ] - [ 2025-01-31 ]
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### Fixed
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‎docs/_static/swap2cz.png‎

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‎docs/tutorial.md‎

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@@ -207,7 +207,7 @@ _Output_:
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qubit[1] q
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Anonymous gate: BlochSphereRotation(Qubit[0], axis=[1. 0. 0.], angle=3.14159, phase=0.0)
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BlochSphereRotation(qubit=Qubit[0], axis=[1. 0. 0.], angle=3.14159, phase=0.0)
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In the above example, OpenSquirrel has merged all the Rx gates together.
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Yet, for now, OpenSquirrel does not recognize that this results in a single Rx
@@ -387,6 +387,14 @@ The decomposition is illustrated in the image below.
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<p align="center"> <img width="600" src="_static/swap2cnot.png"> </p>
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##### _`SWAP` to `CZ` decomposer_
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The `SWAP2CZDecomposer` implements the predefined decomposition of the `SWAP` gate into `Ry` rotations and 3 `CZ`
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gates.
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The decomposition is illustrated in the image below.
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<p align="center"> <img width="600" src="_static/swap2cz.png"> </p>
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#### 2. Inferred decomposition
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@@ -435,9 +443,9 @@ print(ZYZDecomposer().decompose(H(0)))
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```
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_Output_:
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[BlochSphereRotation(Qubit[0], axis=Axis[0. 0. 1.], angle=1.5707963267948966, phase=0.0),
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BlochSphereRotation(Qubit[0], axis=Axis[0. 1. 0.], angle=1.5707963267948966, phase=0.0),
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BlochSphereRotation(Qubit[0], axis=Axis[0. 0. 1.], angle=1.5707963267948966, phase=0.0)]
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[BlochSphereRotation(qubit=Qubit[0], axis=Axis[0. 0. 1.], angle=1.5707963267948966, phase=0.0),
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BlochSphereRotation(qubit=Qubit[0], axis=Axis[0. 1. 0.], angle=1.5707963267948966, phase=0.0),
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BlochSphereRotation(qubit=Qubit[0], axis=Axis[0. 0. 1.], angle=1.5707963267948966, phase=0.0)]
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## Exporting a circuit

‎example/decompositions.ipynb‎

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"\n",
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"The ABA decomposition (or KAK decomposition) is a decomposition method that uses three consecutive Pauli rotation gates to form any unitary gate. Thus, any arbitrary single qubit gate can be expressed as a product of rotations: a rotation around the A axis, followed by a rotation around the B axis, and then another rotation around the A axis. The mathematical formalism for this rotation can be seen in section 3.1.\n",
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"\n",
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"In OpenSquirrel, this can be found in the `get_decomposition_angles` method from the `opensquirrel.decomposer.aba_decomposer` module. The ABA Decomposition can be applied to list of gates or a circuit. Below we will first focus on decomposing a circuit.\n",
20+
"In OpenSquirrel, this can be found in the `get_decomposition_angles` method from the `opensquirrel.passes.decomposer.aba_decomposer` module. The ABA Decomposition can be applied to list of gates or a circuit. Below we will first focus on decomposing a circuit.\n",
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"\n",
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"The circuit chosen is a single qubit circuit with an added Hadamard, Z, Y, and Rx gate. \n",
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"\n",
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"source": [
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"import math\n",
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"\n",
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"from opensquirrel import CircuitBuilder\n",
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"from opensquirrel.ir import Float, Qubit\n",
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"from opensquirrel.circuit_builder import CircuitBuilder\n",
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"\n",
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"# Build the circuit structure using the CircuitBuilder\n",
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"builder = CircuitBuilder(qubit_register_size=1)\n",
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"builder.H(Qubit(0))\n",
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"builder.Z(Qubit(0))\n",
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"builder.Y(Qubit(0))\n",
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"builder.Rx(Qubit(0), Float(math.pi / 3))\n",
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"builder.H(0)\n",
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"builder.Z(0)\n",
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"builder.Y(0)\n",
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"builder.Rx(0, math.pi / 3)\n",
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"\n",
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"# Create a new circuit from the constructed structure\n",
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"circuit = builder.to_circuit()\n",
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"cell_type": "markdown",
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"id": "afe111839ab98b22",
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"metadata": {},
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"source": "Above we can see the current gates in our circuit. Having created a circuit, we can now use an ABA decomposition in `opensquirrel.decomposer.aba_decomposer` to decompose the gates in the circuit. For this example, we will apply the Z-Y-Z decomposition using the `ZYZDecomposer`. "
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"source": [
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"Above we can see the current gates in our circuit. Having created a circuit, we can now use an ABA decomposition in `opensquirrel.passes.decomposer.aba_decomposer` to decompose the gates in the circuit. For this example, we will apply the Z-Y-Z decomposition using the `ZYZDecomposer`. "
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]
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},
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{
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"cell_type": "code",
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}
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],
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"source": [
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"from opensquirrel.passes.decomposer import ZYZDecomposer\n",
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"from opensquirrel.passes.decomposer.aba_decomposer import ZYZDecomposer\n",
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"\n",
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"# Decompose the circuit using ZYZDecomposer\n",
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"circuit.decompose(decomposer=ZYZDecomposer())\n",
@@ -170,9 +171,9 @@
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],
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"source": [
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"from opensquirrel import H\n",
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"from opensquirrel.passes.decomposer import XZXDecomposer\n",
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"from opensquirrel.passes.decomposer.aba_decomposer import XZXDecomposer\n",
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"\n",
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"XZXDecomposer().decompose(H(Qubit(0)))"
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"XZXDecomposer().decompose(H(0))"
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]
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},
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{
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"source": [
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"# Build the circuit structure using the CircuitBuilder\n",
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"builder = CircuitBuilder(qubit_register_size=1)\n",
229-
"builder.H(Qubit(0))\n",
230-
"builder.Z(Qubit(0))\n",
231-
"builder.X(Qubit(0))\n",
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"builder.Rx(Qubit(0), Float(math.pi / 3))\n",
230+
"builder.H(0)\n",
231+
"builder.Z(0)\n",
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"builder.X(0)\n",
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"builder.Rx(0, math.pi / 3)\n",
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"\n",
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"# Create a new circuit from the constructed structure\n",
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"circuit = builder.to_circuit()\n",
@@ -240,7 +241,9 @@
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"cell_type": "markdown",
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"id": "69517d8287c1777d",
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"metadata": {},
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"source": "The `McKayDecomposer` is called from `opensquirrel.decomposer.mckay_decomposer` and used in a similar method to the `ABADecomposer`."
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"source": [
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"The `McKayDecomposer` is called from `opensquirrel.passes.decomposer` and used in a similar method to the `ABADecomposer`."
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]
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},
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{
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"cell_type": "code",
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"source": [
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"# Build the circuit structure using the CircuitBuilder\n",
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"builder = CircuitBuilder(qubit_register_size=2)\n",
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"builder.CZ(Qubit(0), Qubit(1))\n",
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"builder.CR(Qubit(0), Qubit(1), Float(math.pi / 3))\n",
363-
"builder.CR(Qubit(1), Qubit(0), Float(math.pi / 2))\n",
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"builder.CZ(0, 1)\n",
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"builder.CR(0, 1, math.pi / 3)\n",
366+
"builder.CR(1, 0, math.pi / 2)\n",
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"\n",
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"# Create a new circuit from the constructed structure\n",
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"circuit = builder.to_circuit()\n",
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"cell_type": "markdown",
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"id": "8c945ab4572e9f77",
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"metadata": {},
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"source": "We can import `CNOTDecomposer` from `opensquirrel.decomposer.cnot_decomposer`. The above circuit can then be decomposed using `CNOTDecomposer` as seen below."
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"source": [
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"We can import `CNOTDecomposer` from `opensquirrel.passes.decomposer`. The above circuit can then be decomposed using `CNOTDecomposer` as seen below."
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]
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},
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{
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"cell_type": "code",
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"outputs": [
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{
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"data": {
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"text/latex": "$\\displaystyle \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{1} + \\theta_{3}}{2} \\right)} + - \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\sin{\\left(\\frac{\\theta_{1} - \\theta_{3}}{2} \\right)} i + \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{1} - \\theta_{3}}{2} \\right)} j + \\sin{\\left(\\frac{\\theta_{1} + \\theta_{3}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} k$",
483+
"text/latex": [
484+
"$\\displaystyle \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{1} + \\theta_{3}}{2} \\right)} + - \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\sin{\\left(\\frac{\\theta_{1} - \\theta_{3}}{2} \\right)} i + \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{1} - \\theta_{3}}{2} \\right)} j + \\sin{\\left(\\frac{\\theta_{1} + \\theta_{3}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} k$"
485+
],
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"text/plain": [
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"cos(theta_2/2)*cos((theta_1 + theta_3)/2) + (-sin(theta_2/2)*sin((theta_1 - theta_3)/2))*i + sin(theta_2/2)*cos((theta_1 - theta_3)/2)*j + sin((theta_1 + theta_3)/2)*cos(theta_2/2)*k"
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]
@@ -502,7 +509,9 @@
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"cell_type": "markdown",
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"id": "6e776f2cb7cae465",
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"metadata": {},
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"source": "Let us change variables and define $p\\equiv\\theta_1 + \\theta_3$ and $m\\equiv\\theta_1 - \\theta_3$."
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"source": [
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"Let us change variables and define $p\\equiv\\theta_1 + \\theta_3$ and $m\\equiv\\theta_1 - \\theta_3$."
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]
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},
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{
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"cell_type": "code",
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"outputs": [
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{
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"data": {
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"text/latex": "$\\displaystyle \\cos{\\left(\\frac{p}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} + - \\sin{\\left(\\frac{m}{2} \\right)} \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} i + \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{m}{2} \\right)} j + \\sin{\\left(\\frac{p}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} k$",
529+
"text/latex": [
530+
"$\\displaystyle \\cos{\\left(\\frac{p}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} + - \\sin{\\left(\\frac{m}{2} \\right)} \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} i + \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{m}{2} \\right)} j + \\sin{\\left(\\frac{p}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} k$"
531+
],
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"text/plain": [
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"cos(p/2)*cos(theta_2/2) + (-sin(m/2)*sin(theta_2/2))*i + sin(theta_2/2)*cos(m/2)*j + sin(p/2)*cos(theta_2/2)*k"
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]
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"cell_type": "markdown",
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"id": "1ece3d36eb99512b",
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"metadata": {},
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"source": "The original rotation's quaternion $q$ can be defined in Sympy accordingly:"
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"source": [
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"The original rotation's quaternion $q$ can be defined in Sympy accordingly:"
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]
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},
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{
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"cell_type": "code",
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"outputs": [
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{
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"data": {
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"text/latex": "$\\displaystyle \\cos{\\left(\\frac{\\alpha}{2} \\right)} + n_{x} \\sin{\\left(\\frac{\\alpha}{2} \\right)} i + n_{y} \\sin{\\left(\\frac{\\alpha}{2} \\right)} j + n_{z} \\sin{\\left(\\frac{\\alpha}{2} \\right)} k$",
570+
"text/latex": [
571+
"$\\displaystyle \\cos{\\left(\\frac{\\alpha}{2} \\right)} + n_{x} \\sin{\\left(\\frac{\\alpha}{2} \\right)} i + n_{y} \\sin{\\left(\\frac{\\alpha}{2} \\right)} j + n_{z} \\sin{\\left(\\frac{\\alpha}{2} \\right)} k$"
572+
],
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"text/plain": [
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"cos(alpha/2) + n_x*sin(alpha/2)*i + n_y*sin(alpha/2)*j + n_z*sin(alpha/2)*k"
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]
@@ -577,7 +592,9 @@
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"cell_type": "markdown",
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"id": "7cb50842c8fa111a",
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"metadata": {},
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"source": "We get the following system of equations, where the unknowns are $p$, $m$, and $\\theta_2$:\n"
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"source": [
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"We get the following system of equations, where the unknowns are $p$, $m$, and $\\theta_2$:\n"
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]
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},
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{
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"cell_type": "code",
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"outputs": [
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{
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"data": {
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"text/latex": "$\\displaystyle \\cos{\\left(\\frac{p}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} = \\cos{\\left(\\frac{\\alpha}{2} \\right)}$",
612+
"text/latex": [
613+
"$\\displaystyle \\cos{\\left(\\frac{p}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} = \\cos{\\left(\\frac{\\alpha}{2} \\right)}$"
614+
],
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"text/plain": [
597616
"Eq(cos(p/2)*cos(theta_2/2), cos(alpha/2))"
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]
@@ -602,7 +621,9 @@
602621
},
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{
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"data": {
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"text/latex": "$\\displaystyle - \\sin{\\left(\\frac{m}{2} \\right)} \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} = n_{x} \\sin{\\left(\\frac{\\alpha}{2} \\right)}$",
624+
"text/latex": [
625+
"$\\displaystyle - \\sin{\\left(\\frac{m}{2} \\right)} \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} = n_{x} \\sin{\\left(\\frac{\\alpha}{2} \\right)}$"
626+
],
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"text/plain": [
607628
"Eq(-sin(m/2)*sin(theta_2/2), n_x*sin(alpha/2))"
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]
@@ -612,7 +633,9 @@
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},
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{
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"data": {
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"text/latex": "$\\displaystyle \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{m}{2} \\right)} = n_{y} \\sin{\\left(\\frac{\\alpha}{2} \\right)}$",
636+
"text/latex": [
637+
"$\\displaystyle \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{m}{2} \\right)} = n_{y} \\sin{\\left(\\frac{\\alpha}{2} \\right)}$"
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],
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"text/plain": [
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"Eq(sin(theta_2/2)*cos(m/2), n_y*sin(alpha/2))"
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]
@@ -622,7 +645,9 @@
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},
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{
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"data": {
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"text/latex": "$\\displaystyle \\sin{\\left(\\frac{p}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} = n_{z} \\sin{\\left(\\frac{\\alpha}{2} \\right)}$",
648+
"text/latex": [
649+
"$\\displaystyle \\sin{\\left(\\frac{p}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} = n_{z} \\sin{\\left(\\frac{\\alpha}{2} \\right)}$"
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],
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"text/plain": [
627652
"Eq(sin(p/2)*cos(theta_2/2), n_z*sin(alpha/2))"
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]
@@ -646,7 +671,9 @@
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"cell_type": "markdown",
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"id": "e6b34ef9cb46f2e4",
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"metadata": {},
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"source": "Instead, assume $\\sin(p/2) \\neq 0$, then we can substitute in the first equation $\\cos\\left(\\theta_2/2\\right)$ with its value computed from the last equation. We get:"
674+
"source": [
675+
"Instead, assume $\\sin(p/2) \\neq 0$, then we can substitute in the first equation $\\cos\\left(\\theta_2/2\\right)$ with its value computed from the last equation. We get:"
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]
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},
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{
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"cell_type": "code",
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"outputs": [
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{
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"data": {
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"text/latex": "$\\displaystyle \\frac{n_{z} \\sin{\\left(\\frac{\\alpha}{2} \\right)}}{\\tan{\\left(\\frac{p}{2} \\right)}} = \\cos{\\left(\\frac{\\alpha}{2} \\right)}$",
691+
"text/latex": [
692+
"$\\displaystyle \\frac{n_{z} \\sin{\\left(\\frac{\\alpha}{2} \\right)}}{\\tan{\\left(\\frac{p}{2} \\right)}} = \\cos{\\left(\\frac{\\alpha}{2} \\right)}$"
693+
],
665694
"text/plain": [
666695
"Eq(n_z*sin(alpha/2)/tan(p/2), cos(alpha/2))"
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]
@@ -718,7 +747,9 @@
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"cell_type": "markdown",
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"id": "e3fc4cdb6d15dd1",
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"metadata": {},
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"source": "The terms are similar to the other decompositions, XZX, YXY, ZXZ, XYX and YZY. However, for ZXZ, XYX and YZY, the $i$ term in the quaternion is positive as seen below in the YZY decomposition."
750+
"source": [
751+
"The terms are similar to the other decompositions, XZX, YXY, ZXZ, XYX and YZY. However, for ZXZ, XYX and YZY, the $i$ term in the quaternion is positive as seen below in the YZY decomposition."
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]
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},
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{
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"cell_type": "code",
@@ -733,7 +764,9 @@
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"outputs": [
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{
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"data": {
736-
"text/latex": "$\\displaystyle \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{1} + \\theta_{3}}{2} \\right)} + \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\sin{\\left(\\frac{\\theta_{1} - \\theta_{3}}{2} \\right)} i + \\sin{\\left(\\frac{\\theta_{1} + \\theta_{3}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} j + \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{1} - \\theta_{3}}{2} \\right)} k$",
767+
"text/latex": [
768+
"$\\displaystyle \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{1} + \\theta_{3}}{2} \\right)} + \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\sin{\\left(\\frac{\\theta_{1} - \\theta_{3}}{2} \\right)} i + \\sin{\\left(\\frac{\\theta_{1} + \\theta_{3}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{2}}{2} \\right)} j + \\sin{\\left(\\frac{\\theta_{2}}{2} \\right)} \\cos{\\left(\\frac{\\theta_{1} - \\theta_{3}}{2} \\right)} k$"
769+
],
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"text/plain": [
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"cos(theta_2/2)*cos((theta_1 + theta_3)/2) + sin(theta_2/2)*sin((theta_1 - theta_3)/2)*i + sin((theta_1 + theta_3)/2)*cos(theta_2/2)*j + sin(theta_2/2)*cos((theta_1 - theta_3)/2)*k"
739772
]
@@ -758,7 +791,9 @@
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"cell_type": "markdown",
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"id": "a41b84ed5f3365b2",
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"metadata": {},
761-
"source": "Thus, in order to correct for the orientation of the rotation, $\\theta_1$ and $\\theta_3$ are swapped. "
794+
"source": [
795+
"Thus, in order to correct for the orientation of the rotation, $\\theta_1$ and $\\theta_3$ are swapped. "
796+
]
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},
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{
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"cell_type": "markdown",
@@ -793,6 +828,8 @@
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},
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{
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"cell_type": "markdown",
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"id": "866e89a24587f0af",
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"metadata": {},
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"source": [
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"### 3.3 ABA Decomposition\n",
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"In a two qubit system, the unitary matrix of a controlled operation is seen below,\n",
@@ -844,11 +881,20 @@
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"C &= Rz\\bigg(\\frac{1}{2} \\theta_0 - \\frac{1}{2} \\theta_2 \\bigg)\n",
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"\\end{split}\n",
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"$$"
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],
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]
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},
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{
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"cell_type": "code",
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"execution_count": 28,
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"id": "3cc1e9963f3e794d",
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"metadata": {
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"collapsed": false
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"ExecuteTime": {
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"end_time": "2024-08-05T11:35:27.882752Z",
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"start_time": "2024-08-05T11:35:27.871794Z"
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}
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},
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"id": "c084046b0bb17ec9"
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"outputs": [],
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"source": []
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}
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],
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"metadata": {

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