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Copy path59_SpiralMatrix2.py
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39 lines (34 loc) · 1021 Bytes
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# -*- coding: utf-8 -*-
# @File : 59_SpiralMatrix2.py
# @Author: ZRN
# @Date : 2019/4/29
"""
给定一个正整数 n,生成一个包含 1 到 n^2 所有元素,且元素按顺时针顺序螺旋排列的正方形矩阵。
"""
class Solution:
def generateMatrix(self, n):
m = [[0] * n for i in range(n)]
center = n // 2
num = 1
for i in range(center):
steps = n - i * 2 - 1
for j in range(steps):
m[i][i + j] = num
num += 1
for j in range(steps):
m[i + j][i + steps] = num
num += 1
for j in range(steps):
m[i + steps][i + steps - j] = num
num += 1
for j in range(steps):
m[i + steps - j][i] = num
num += 1
if n % 2 == 1:
m[center][center] = num
return m
if __name__ == '__main__':
s = Solution()
m = s.generateMatrix(1)
for i in m:
print(i)