-
Notifications
You must be signed in to change notification settings - Fork 22
/
Copy pathStudentsAndExaminations.sql
133 lines (116 loc) · 4.43 KB
/
StudentsAndExaminations.sql
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
-- Table: Students
-- +---------------+---------+
-- | Column Name | Type |
-- +---------------+---------+
-- | student_id | int |
-- | student_name | varchar |
-- +---------------+---------+
-- student_id is the primary key (column with unique values) for this table.
-- Each row of this table contains the ID and the name of one student in the school.
-- Table: Subjects
-- +--------------+---------+
-- | Column Name | Type |
-- +--------------+---------+
-- | subject_name | varchar |
-- +--------------+---------+
-- subject_name is the primary key (column with unique values) for this table.
-- Each row of this table contains the name of one subject in the school.
-- Table: Examinations
-- +--------------+---------+
-- | Column Name | Type |
-- +--------------+---------+
-- | student_id | int |
-- | subject_name | varchar |
-- +--------------+---------+
-- There is no primary key (column with unique values) for this table. It may contain duplicates.
-- Each student from the Students table takes every course from the Subjects table.
-- Each row of this table indicates that a student with ID student_id attended the exam of subject_name.
-- Write a solution to find the number of times each student attended each exam.
-- Return the result table ordered by student_id and subject_name.
-- The result format is in the following example.
-- Example 1:
-- Input:
-- Students table:
-- +------------+--------------+
-- | student_id | student_name |
-- +------------+--------------+
-- | 1 | Alice |
-- | 2 | Bob |
-- | 13 | John |
-- | 6 | Alex |
-- +------------+--------------+
-- Subjects table:
-- +--------------+
-- | subject_name |
-- +--------------+
-- | Math |
-- | Physics |
-- | Programming |
-- +--------------+
-- Examinations table:
-- +------------+--------------+
-- | student_id | subject_name |
-- +------------+--------------+
-- | 1 | Math |
-- | 1 | Physics |
-- | 1 | Programming |
-- | 2 | Programming |
-- | 1 | Physics |
-- | 1 | Math |
-- | 13 | Math |
-- | 13 | Programming |
-- | 13 | Physics |
-- | 2 | Math |
-- | 1 | Math |
-- +------------+--------------+
-- Output:
-- +------------+--------------+--------------+----------------+
-- | student_id | student_name | subject_name | attended_exams |
-- +------------+--------------+--------------+----------------+
-- | 1 | Alice | Math | 3 |
-- | 1 | Alice | Physics | 2 |
-- | 1 | Alice | Programming | 1 |
-- | 2 | Bob | Math | 1 |
-- | 2 | Bob | Physics | 0 |
-- | 2 | Bob | Programming | 1 |
-- | 6 | Alex | Math | 0 |
-- | 6 | Alex | Physics | 0 |
-- | 6 | Alex | Programming | 0 |
-- | 13 | John | Math | 1 |
-- | 13 | John | Physics | 1 |
-- | 13 | John | Programming | 1 |
-- +------------+--------------+--------------+----------------+
-- Explanation:
-- The result table should contain all students and all subjects.
-- Alice attended the Math exam 3 times, the Physics exam 2 times, and the Programming exam 1 time.
-- Bob attended the Math exam 1 time, the Programming exam 1 time, and did not attend the Physics exam.
-- Alex did not attend any exams.
-- John attended the Math exam 1 time, the Physics exam 1 time, and the Programming exam 1 time.
-- Solution in PostgreSQL
with combined_dataset as
(
select s.student_id,
s.student_name,
sub.subject_name
from students s
cross join subjects sub
)
select cd.student_id,
cd.student_name,
cd.subject_name,
case when ae.attended_exams is null then 0
else ae.attended_exams
end as attended_exams
from combined_dataset cd
left join
(
select student_id,
subject_name,
count(*) as attended_exams
from Examinations
group by student_id,
subject_name
) ae
on (cd.student_id = ae.student_id
and cd.subject_name = ae.subject_name)
order by cd.student_id,cd.subject_name;