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| 1 | +/* |
| 2 | +
|
| 3 | +-* 224. Basic Calculator *- |
| 4 | +
|
| 5 | +Given a string s representing a valid expression, implement a basic calculator to evaluate it, and return the result of the evaluation. |
| 6 | +
|
| 7 | +Note: You are not allowed to use any built-in function which evaluates strings as mathematical expressions, such as eval(). |
| 8 | +
|
| 9 | +
|
| 10 | +
|
| 11 | +Example 1: |
| 12 | +
|
| 13 | +Input: s = "1 + 1" |
| 14 | +Output: 2 |
| 15 | +Example 2: |
| 16 | +
|
| 17 | +Input: s = " 2-1 + 2 " |
| 18 | +Output: 3 |
| 19 | +Example 3: |
| 20 | +
|
| 21 | +Input: s = "(1+(4+5+2)-3)+(6+8)" |
| 22 | +Output: 23 |
| 23 | +
|
| 24 | +
|
| 25 | +Constraints: |
| 26 | +
|
| 27 | +1 <= s.length <= 3 * 105 |
| 28 | +s consists of digits, '+', '-', '(', ')', and ' '. |
| 29 | +s represents a valid expression. |
| 30 | +'+' is not used as a unary operation (i.e., "+1" and "+(2 + 3)" is invalid). |
| 31 | +'-' could be used as a unary operation (i.e., "-1" and "-(2 + 3)" is valid). |
| 32 | +There will be no two consecutive operators in the input. |
| 33 | +Every number and running calculation will fit in a signed 32-bit integer. |
| 34 | +
|
| 35 | +*/ |
| 36 | +import 'dart:collection'; |
| 37 | + |
| 38 | +class A { |
| 39 | + int calculate(String s) { |
| 40 | + int sign = 1; |
| 41 | + int result = 0; |
| 42 | + int number = 0; |
| 43 | + |
| 44 | + int n = s.length; |
| 45 | + List<int> st = []; |
| 46 | + |
| 47 | + for (int i = 0; i < n; i++) { |
| 48 | + String c = s[i]; |
| 49 | + if (c.codeUnitAt(0) >= '0'.codeUnitAt(0) && |
| 50 | + c.codeUnitAt(0) <= '9'.codeUnitAt(0)) { |
| 51 | + number = number * 10 + (c.codeUnitAt(0) - '0'.codeUnitAt(0)); |
| 52 | + } |
| 53 | + if (c == '-') { |
| 54 | + // number completed. |
| 55 | + // update result |
| 56 | + result += (sign) * (number); |
| 57 | + number = 0; |
| 58 | + sign = -1; |
| 59 | + } |
| 60 | + if (c == '+') { |
| 61 | + // number completed |
| 62 | + // update result |
| 63 | + result += (sign) * (number); |
| 64 | + number = 0; |
| 65 | + sign = 1; |
| 66 | + } |
| 67 | + if (c == '(') { |
| 68 | + // number completed, result updated already before when we encountered +/- before opening bracket |
| 69 | + st.add(result); |
| 70 | + // so that sign remains at the top (signifies sign before opening bracket was encountered) |
| 71 | + st.add(sign); |
| 72 | + result = 0; // building result between brackets from scratch |
| 73 | + sign = 1; |
| 74 | + } |
| 75 | + if (c == ')') { |
| 76 | + // number is completed |
| 77 | + // update result |
| 78 | + result += (sign) * (number); |
| 79 | + number = 0; |
| 80 | + result *= st.first; // multiplying with sign before opening bracket |
| 81 | + st.removeLast(); |
| 82 | + result += st.first; // result constructed before current context. |
| 83 | + st.removeLast(); |
| 84 | + } |
| 85 | + } |
| 86 | + |
| 87 | + // last no space character in case is a number itself , we need to use the number also. |
| 88 | + result += (sign) * number; |
| 89 | + |
| 90 | + return result; |
| 91 | + } |
| 92 | +} |
| 93 | + |
| 94 | +class B { |
| 95 | + bool isDigit(String? s) { |
| 96 | + if (s == null) { |
| 97 | + return false; |
| 98 | + } |
| 99 | + return int.tryParse(s) != null; |
| 100 | + } |
| 101 | + |
| 102 | + int calculate(String s) { |
| 103 | + List<int> stack = []; |
| 104 | + int result = 0; |
| 105 | + int number = 0; |
| 106 | + int sign = 1; |
| 107 | + for (int i = 0; i < s.length; i++) { |
| 108 | + String c = s[i]; |
| 109 | + if (isDigit(c)) { |
| 110 | + number = 10 * number + (c.codeUnitAt(0) - '0'.codeUnitAt(0)); |
| 111 | + } else if (c == '+') { |
| 112 | + result += sign * number; |
| 113 | + number = 0; |
| 114 | + sign = 1; |
| 115 | + } else if (c == '-') { |
| 116 | + result += sign * number; |
| 117 | + number = 0; |
| 118 | + sign = -1; |
| 119 | + } else if (c == '(') { |
| 120 | + //we push the result first, then sign; |
| 121 | + stack.add(result); |
| 122 | + stack.add(sign); |
| 123 | + //reset the sign and result for the value in the parenthesis |
| 124 | + sign = 1; |
| 125 | + result = 0; |
| 126 | + } else if (c == ')') { |
| 127 | + result += sign * number; |
| 128 | + number = 0; |
| 129 | + result *= |
| 130 | + stack.removeLast(); //stack.pop() is the sign before the parenthesis |
| 131 | + result += stack |
| 132 | + .removeLast(); //stack.pop() now is the result calculated before the parenthesis |
| 133 | + |
| 134 | + } |
| 135 | + } |
| 136 | + if (number != 0) result += sign * number; |
| 137 | + return result; |
| 138 | + } |
| 139 | +} |
| 140 | + |
| 141 | +class C { |
| 142 | + bool isDigit(String? s) { |
| 143 | + if (s == null) { |
| 144 | + return false; |
| 145 | + } |
| 146 | + return int.tryParse(s) != null; |
| 147 | + } |
| 148 | + |
| 149 | + int calculate(String s) { |
| 150 | + // all possible case: "+", "-", "(", ")", " ", "1-9" |
| 151 | + // +: change sign to positive +1 |
| 152 | + // -: change sign to negative -1 |
| 153 | + // (: push current result value and sign onto the stack |
| 154 | + // ): pop the previous result value and sign off the stack and do the addition |
| 155 | + // " ": skip |
| 156 | + // 1-9: read all digits after current digit |
| 157 | + Queue<int> stack = Queue(); |
| 158 | + // initialize result to be 0, sign to be 1 |
| 159 | + int res = 0, sign = 1; |
| 160 | + |
| 161 | + int n = s.length; |
| 162 | + // iterate through all characters of the input |
| 163 | + for (int i = 0; i < n; i++) { |
| 164 | + String curr = s[i]; |
| 165 | + switch (curr) { |
| 166 | + case '+': |
| 167 | + // make sign become positive to indicate we are adding a value |
| 168 | + sign = 1; |
| 169 | + break; |
| 170 | + case '-': |
| 171 | + // make sign become negative to indicate we are subtracting a value |
| 172 | + sign = -1; |
| 173 | + break; |
| 174 | + case '(': |
| 175 | + // pushing current result as well as the sign onto the stack |
| 176 | + stack.addFirst(res); |
| 177 | + stack.addFirst(sign); |
| 178 | + // reset result and sign |
| 179 | + res = 0; |
| 180 | + sign = 1; |
| 181 | + break; |
| 182 | + case ')': |
| 183 | + // popping previous result and sign off the stack and do the addition(subtraction) |
| 184 | + // with the current calculation result |
| 185 | + int prevSign = stack.removeFirst(); |
| 186 | + int prevRes = stack.removeFirst(); |
| 187 | + res = prevRes + prevSign * res; |
| 188 | + break; |
| 189 | + case ' ': |
| 190 | + // skip the empty spaces |
| 191 | + break; |
| 192 | + default: |
| 193 | + // in case current char is a digit, read the whole integer |
| 194 | + int startIdx = i; |
| 195 | + while (i < n && isDigit(s[i])) { |
| 196 | + i++; |
| 197 | + } |
| 198 | + int v = int.parse(s.substring(startIdx, i)); |
| 199 | + res += sign * v; |
| 200 | + i--; |
| 201 | + } |
| 202 | + } |
| 203 | + return res; |
| 204 | + } |
| 205 | +} |
| 206 | + |
| 207 | +class D { |
| 208 | + int pos = 0; |
| 209 | + bool isNum(String curr) { |
| 210 | + int nums = curr.codeUnitAt(0) - '0'.codeUnitAt(0); |
| 211 | + return nums >= 0 && nums <= 9; |
| 212 | + } |
| 213 | + |
| 214 | + int solve(String s) { |
| 215 | + int sign = 1; // initial take as positive |
| 216 | + int nums = 0; |
| 217 | + int res = 0; |
| 218 | + while (pos < s.length) { |
| 219 | + String curr = s[pos++]; |
| 220 | + if (curr == ' ') { |
| 221 | + continue; |
| 222 | + } else if (isNum(curr)) { |
| 223 | + nums = nums * 10 + curr.codeUnitAt(0) - '0'.codeUnitAt(0); |
| 224 | + } else if (curr == '(') { |
| 225 | + nums = solve(s); |
| 226 | + } else if (curr == ')') { |
| 227 | + res += nums * sign; |
| 228 | + return res; |
| 229 | + } else { |
| 230 | + res += sign * nums; |
| 231 | + sign = curr == '-' ? -1 : 1; |
| 232 | + nums = 0; |
| 233 | + } |
| 234 | + } |
| 235 | + int ret = res + (sign * nums); |
| 236 | + return ret; |
| 237 | + } |
| 238 | + |
| 239 | + int calculate(String s) { |
| 240 | + pos = 0; |
| 241 | + return solve(s); |
| 242 | + } |
| 243 | +} |
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