Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
Example 1:
Input: nums = [1,3,5,6], target = 5 Output: 2
Example 2:
Input: nums = [1,3,5,6], target = 2 Output: 1
Example 3:
Input: nums = [1,3,5,6], target = 7 Output: 4
Example 4:
Input: nums = [1,3,5,6], target = 0 Output: 0
Example 5:
Input: nums = [1], target = 0 Output: 0
Constraints:
1 <= nums.length <= 104
-104 <= nums[i] <= 104
nums
contains distinct values sorted in ascending order.-104 <= target <= 104
class Solution:
def searchInsert(self, nums: List[int], target: int) -> int:
l, h = 0, len(nums) - 1
while l <= h:
m = (l + h) >> 1
if nums[m] == target:
return m
if nums[m] < target:
l = m + 1
else:
h = m - 1
return l
class Solution {
public int searchInsert(int[] nums, int target) {
int l = 0, h = nums.length - 1;
while (l <= h) {
int m = (l + h) >>> 1;
if (nums[m] == target) return m;
if (nums[m] < target) l = m + 1;
else h = m - 1;
}
return l;
}
}
func searchInsert(nums []int, target int) int {
l, h := 0, len(nums) - 1
for l <= h {
m := l + ((h - l) >> 1)
if nums[m] == target {
return m
}
if nums[m] < target {
l = m + 1
} else {
h = m - 1
}
}
return l
}
class Solution {
public:
int searchInsert(vector<int>& nums, int target) {
int l = 0, h = nums.size() - 1;
while (l <= h) {
int m = l + ((h - l) >> 1);
if (nums[m] == target) return m;
if (nums[m] < target) l = m + 1;
else h = m - 1;
}
return l;
}
};
/**
* @param {number[]} nums
* @param {number} target
* @return {number}
*/
var searchInsert = function (nums, target) {
let l = 0,
h = nums.length;
while (l <= h) {
const m = (l + h) >>> 1;
if (nums[m] == target) return m;
if (nums[m] < target) l = m + 1;
else h = m - 1;
}
return l;
};