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893. 特殊等价字符串组

你将得到一个字符串数组 A

如果经过任意次数的移动,S == T,那么两个字符串 ST特殊等价的。

一次移动包括选择两个索引 ij,且 i % 2 == j % 2,交换 S[j]S [i]

现在规定,A 中的特殊等价字符串组A 的非空子集 S,这样不在 S 中的任何字符串与 S 中的任何字符串都不是特殊等价的。

返回 A 中特殊等价字符串组的数量。

示例 1:

输入: ["a","b","c","a","c","c"]
输出: 3
解释: 3 组 ["a","a"],["b"],["c","c","c"]

示例 2:

输入: ["aa","bb","ab","ba"]
输出: 4
解释: 4 组 ["aa"],["bb"],["ab"],["ba"]

示例 3:

输入: ["abc","acb","bac","bca","cab","cba"]
输出: 3
解释: 3 组 ["abc","cba"],["acb","bca"],["bac","cab"]

示例 4:

输入: ["abcd","cdab","adcb","cbad"]
输出: 1
解释: 1 组 ["abcd","cdab","adcb","cbad"]

提示:

  • 1 <= A.length <= 1000
  • 1 <= A[i].length <= 20
  • 所有 A[i] 都具有相同的长度。
  • 所有 A[i] 都只由小写字母组成。

题解 (Rust)

1. 计数

use std::collections::HashSet;

impl Solution {
    pub fn num_special_equiv_groups(a: Vec<String>) -> i32 {
        let mut set = HashSet::new();

        for s in a {
            let mut cnt = vec![0; 52];
            for (i, c) in s.bytes().enumerate() {
                cnt[(c - b'a') as usize + 26 * (i % 2)] += 1;
            }
            set.insert(cnt);
        }

        set.len() as i32
    }
}