@Solution: Find All Possible Recipes from Given Supplies

Author: i-redbyte

medium/find all possible recipes from given supplies/README.md

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+# Find All Possible Recipes from Given Supplies
+
+You have information about n different recipes. You are given a string array recipes and a 2D string array ingredients. The ith recipe has the name recipes[i], and you can create it if you have all the needed ingredients from ingredients[i]. A recipe can also be an ingredient for other recipes, i.e., ingredients[i] may contain a string that is in recipes.
+
+You are also given a string array supplies containing all the ingredients that you initially have, and you have an infinite supply of all of them.
+
+Return a list of all the recipes that you can create. You may return the answer in any order.
+
+Note that two recipes may contain each other in their ingredients.
+
+
+Example 1:
+
+```
+Input: recipes = ["bread"], ingredients = [["yeast","flour"]], supplies = ["yeast","flour","corn"]
+Output: ["bread"]
+Explanation:
+We can create "bread" since we have the ingredients "yeast" and "flour".
+```
+
+Example 2:
+
+```
+Input: recipes = ["bread","sandwich"], ingredients = [["yeast","flour"],["bread","meat"]], supplies = ["yeast","flour","meat"]
+Output: ["bread","sandwich"]
+Explanation:
+We can create "bread" since we have the ingredients "yeast" and "flour".
+We can create "sandwich" since we have the ingredient "meat" and can create the ingredient "bread".
+```
+Example 3:
+
+```
+Input: recipes = ["bread","sandwich","burger"], ingredients = [["yeast","flour"],["bread","meat"],["sandwich","meat","bread"]], supplies = ["yeast","flour","meat"]
+Output: ["bread","sandwich","burger"]
+Explanation:
+We can create "bread" since we have the ingredients "yeast" and "flour".
+We can create "sandwich" since we have the ingredient "meat" and can create the ingredient "bread".
+We can create "burger" since we have the ingredient "meat" and can create the ingredients "bread" and "sandwich".
+```
+
+**Constraints:**
+- n == recipes.length == ingredients.length
+- 1 <= n <= 100
+- 1 <= ingredients[i].length, supplies.length <= 100
+- 1 <= recipes[i].length, ingredients[i][j].length, supplies[k].length <= 10
+- recipes[i], ingredients[i][j], and supplies[k] consist only of lowercase English letters.
+- All the values of recipes and supplies combined are unique.
+- Each ingredients[i] does not contain any duplicate values.
+
+[Link](https://leetcode.com/problems/find-all-possible-recipes-from-given-supplies/description)

medium/find all possible recipes from given supplies/solution.py

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+from typing import List
+
+
+class Solution:
+    def findAllRecipes(self, recipes: List[str], ingredients: List[List[str]], supplies: List[str]) -> List[str]:
+        recipe_to_ingredients = {recipe: set(ingr) for recipe, ingr in zip(recipes, ingredients)}
+        available_supplies = set(supplies)
+        result: List[str] = []
+        recipes_to_check = set(recipes)
+
+        def can_cook(recipe: str) -> bool:
+            for ingredient in recipe_to_ingredients[recipe]:
+                if ingredient not in available_supplies:
+                    return False
+            return True
+
+        while recipes_to_check:
+            removable_recipes = []
+
+            for recipe in recipes_to_check:
+                if can_cook(recipe):
+                    result.append(recipe)
+                    available_supplies.add(recipe)
+                    removable_recipes.append(recipe)
+
+            for recipe in removable_recipes:
+                recipes_to_check.remove(recipe)
+
+            if not removable_recipes:
+                break
+
+        return result
+
+
+s = Solution()
+print(s.findAllRecipes(recipes=["bread"], ingredients=[["yeast", "flour"]], supplies=["yeast", "flour", "corn"]))
+print(s.findAllRecipes(recipes=["bread", "sandwich"], ingredients=[["yeast", "flour"], ["bread", "meat"]],
+                       supplies=["yeast", "flour", "meat"]))
+print(s.findAllRecipes(recipes=["bread", "sandwich", "burger"],
+                       ingredients=[["yeast", "flour"], ["bread", "meat"], ["sandwich", "meat", "bread"]],
+                       supplies=["yeast", "flour", "meat"]))