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testFactorial1 not solvable with "Refl" #54

@peterb12

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@peterb12

Using "Refl" as the solution for test_factorial1 (or 2) yields:

 |   When checking right hand side of testFactorial1 with expected type
 |           factorial 3 = 6
 |   
 |   Type mismatch between
 |           6 = 6 (Type of Refl)
 |   and
 |           factorial 3 = 6 (Expected type)
 |   
 |   Specifically:
 |           Type mismatch between
 |                   6
 |           and
 |                   factorial 3

This is important because (1) no other tactics have been introduced at this point and (2) later in the chapter, we explicitly claim that it is solvable that way:

Now that we've defined a few datatypes and functions, let's turn to stating and
proving properties of their behavior. Actually, we've already started doing
this: each of the functions beginning with \idr{test} in the previous sections
makes a precise claim about the behavior of some function on some particular
inputs. The proofs of these claims were always the same: use \idr{Refl} to check
that both sides contain identical values.

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