lab-sql-select.sql

SELECT 
    a.au_id AS "AUTHOR ID",
    a.au_lname AS "LAST NAME",
    a.au_fname AS "FIRST NAME",
    t.title AS "TITLE",
    p.pub_name AS "PUBLISHER"
FROM authors a
JOIN titleauthor ta ON a.au_id = ta.au_id
JOIN titles t ON ta.title_id = t.title_id
JOIN publishers p ON t.pub_id = p.pub_id;


SELECT 
    a.au_id AS "AUTHOR ID",
    a.au_lname AS "LAST NAME",
    a.au_fname AS "FIRST NAME",
    p.pub_name AS "PUBLISHER",
    COUNT(t.title_id) AS "TITLE COUNT"
FROM authors a
JOIN titleauthor ta ON a.au_id = ta.au_id
JOIN titles t ON ta.title_id = t.title_id
JOIN publishers p ON t.pub_id = p.pub_id
GROUP BY a.au_id, a.au_lname, a.au_fname, p.pub_name
ORDER BY a.au_id, p.pub_name;

SELECT 
    a.au_id AS "AUTHOR ID",
    a.au_lname AS "LAST NAME",
    a.au_fname AS "FIRST NAME",
    SUM(s.qty) AS "TOTAL"
FROM authors a
JOIN titleauthor ta ON a.au_id = ta.au_id
JOIN titles t ON ta.title_id = t.title_id
JOIN sales s ON t.title_id = s.title_id
GROUP BY a.au_id, a.au_lname, a.au_fname
ORDER BY TOTAL DESC
LIMIT 3;

SELECT 
    a.au_id AS "AUTHOR ID",
    a.au_lname AS "LAST NAME",
    a.au_fname AS "FIRST NAME",
    COALESCE(SUM(s.qty), 0) AS "TOTAL"
FROM authors a
LEFT JOIN titleauthor ta ON a.au_id = ta.au_id
LEFT JOIN titles t ON ta.title_id = t.title_id
LEFT JOIN sales s ON t.title_id = s.title_id
GROUP BY a.au_id, a.au_lname, a.au_fname
ORDER BY TOTAL DESC;