From a32bc3eb1837fc00a44e0269aacae02fc602cb0e Mon Sep 17 00:00:00 2001
From: Azhar <azharcodes@gmail.com>
Date: Wed, 29 Apr 2020 18:27:04 +0530
Subject: [PATCH 1/5] add: Spiral matrix

---
 Spiral Matrix/Images/spiral-matrix.jpg        | Bin 0 -> 26682 bytes
 Spiral Matrix/README.markdown                 | 154 ++++++++++++++++++
 .../spiral-matrix.playground/Contents.swift   | 103 ++++++++++++
 .../contents.xcplayground                     |   4 +
 .../contents.xcworkspacedata                  |   7 +
 .../xcshareddata/IDEWorkspaceChecks.plist     |   8 +
 6 files changed, 276 insertions(+)
 create mode 100644 Spiral Matrix/Images/spiral-matrix.jpg
 create mode 100644 Spiral Matrix/README.markdown
 create mode 100644 Spiral Matrix/spiral-matrix.playground/Contents.swift
 create mode 100644 Spiral Matrix/spiral-matrix.playground/contents.xcplayground
 create mode 100644 Spiral Matrix/spiral-matrix.playground/playground.xcworkspace/contents.xcworkspacedata
 create mode 100644 Spiral Matrix/spiral-matrix.playground/playground.xcworkspace/xcshareddata/IDEWorkspaceChecks.plist

diff --git a/Spiral Matrix/Images/spiral-matrix.jpg b/Spiral Matrix/Images/spiral-matrix.jpg
new file mode 100644
index 0000000000000000000000000000000000000000..9cc4c8e8675f27cc897c926cc426e5badc14a805
GIT binary patch
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diff --git a/Spiral Matrix/README.markdown b/Spiral Matrix/README.markdown
new file mode 100644
index 000000000..495114b65
--- /dev/null
+++ b/Spiral Matrix/README.markdown	
@@ -0,0 +1,154 @@
+
+## Goal
+Traverse a 2D array in Spiral order.
+
+## Overview
+Given a 2D array, which can be a square array with `n == m`,  we want to return a one-dimensional array of all the elements of the 2D array in spiral order.
+
+Spiral order will start at the top left corner of the 2D array move all the way to the right-most column on that row, then continue in a spiral pattern all the way until every element has been visited.
+
+// image
+
+## Example
+Given the 2D array
+
+```swift
+array = [
+    [1, 2, 3, 4],
+    [12, 13, 14, 5],
+    [11, 16, 15, 6],
+    [10, 9, 8, 7]
+]
+```
+
+we want to traverse this in spiral order and return the following one-dimensional array
+
+```swift
+[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16]
+```
+
+## Iterative approach
+We want to traverse this in clockwise spiral order. We go from the outer-most ‘layer’ to the inner-most ‘ layer’.  
+
+Let’s hold the indices of
+
+```swift
+var startRow = 0
+var startCol = 0
+var endRow = array.count - 1
+var endCol = array[0].count - 1
+```
+
+The order in which we will move through the first layer of the spiral using these indices is
+
+### Steps
+
+1. Loop while `startRow <= endRow, startCol <= endCol`
+2. Horizontally traverse towards the right from `startCol` to (inclusive) `endCol`  by `1`.
+3. Vertically traverse down from `startRow + 1`  to (inclusive) `endRow`  by `1` .
+4. Horizontally traverse towards the left from `endCol - 1`  to (inclusive) `startCol` by `-1`.
+5. Vertically traverse up from `endRow - 1` to (inclusive) `startCol + 1` by `-1`.
+6. Increment indices `startRow += 1` `startCol += 1`
+7. Decrement indices `endRow -= 1` `endCol -= 1`
+
+### Edge cases
+The matrix may have single row or a single columns in the middle. In this case, we don’t want to double-count values during step `4` and `5`, which we have already counted in step `2` and `3`. We will do an index check in both cases and break if it is true.
+
+### Code
+
+```swift
+func spiralTraverse(array: [[Int]]) -> [Int] {
+    guard array.count != 0 else { return [] }
+    
+    var result = [Int]()
+    var startRow = 0
+    var endRow = array.count - 1
+    var startCol = 0
+    var endCol = array[0].count - 1
+    
+    while startRow <= endRow, startCol <= endCol {
+        for col in stride(from: startCol, through: endCol, by: 1) {
+            result.append(array[startRow][col])
+        }
+        
+        for row in stride(from: startRow + 1, through: endRow, by: 1) {
+            result.append(array[row][endCol])
+        }
+        
+        for col in stride(from: endCol - 1, through: startCol, by: -1) {
+            if startRow == endRow {
+                break
+            }
+            result.append(array[endRow][col])
+        }
+        
+        for row in stride(from: endRow - 1, through: startRow + 1, by: -1) {
+            if startCol == endCol {
+                break
+            }
+            result.append(array[row][startCol])
+        }
+        
+        startRow += 1
+        endRow -= 1
+        startCol += 1
+        endCol -= 1
+    }
+    return result
+}
+```
+
+## Recursive approach
+Now let’s check out the recursive implementation of the algorithm. In this version we don’t need to maintain and update indices since we will be calling the function recursively based on different values.
+
+### Code
+```swift
+func spiralTraverse(array: [[Int]]) -> [Int] {
+    var result = [Int]()
+    spiralHelper(array, 0, array.count - 1, 0, array[0].count - 1, &result)
+    return result
+}
+
+func spiralHelper(_ array: [[Int]], _ startRow: Int, _ endRow: Int, _ startCol: Int, _ endCol: Int, _ result: inout [Int]) {
+    if startRow > endRow || startCol > endCol {
+        return
+    }
+    
+    for col in stride(from: startCol, through: endCol, by: 1) {
+        result.append(array[startRow][col])
+    }
+    
+    for row in stride(from: startRow + 1, through: endRow, by: 1) {
+        result.append(array[row][endCol])
+    }
+    
+    for col in stride(from: endCol - 1, through: startCol, by: -1) {
+        if startRow == endRow { break }
+        result.append(array[endRow][col])
+    }
+    
+    for row in stride(from: endRow - 1, through: startRow + 1, by: -1) {
+        if startCol == endCol { break }
+        result.append(array[row][startCol])
+    }
+    
+    spiralHelper(array, startRow + 1, endRow - 1, startCol + 1, endCol - 1, &result)
+}
+```
+
+## Test
+
+```swift
+let array = [
+    [1,2,3,4],
+    [12,13,14,5],
+    [11,16,15,6],
+    [10,9,8,7]
+]
+spiralTraverse(array: array)
+```
+
+## Complexity
+
+* Time: `O(n)` - where `n` is the total number of elements in the 2D array
+* Space: `O(n)` - since we are storing every element of the 2D array into a one-dimensional array
diff --git a/Spiral Matrix/spiral-matrix.playground/Contents.swift b/Spiral Matrix/spiral-matrix.playground/Contents.swift
new file mode 100644
index 000000000..a1b7bdffa
--- /dev/null
+++ b/Spiral Matrix/spiral-matrix.playground/Contents.swift	
@@ -0,0 +1,103 @@
+import Foundation
+
+/**
+ Complexity:
+ Time: O(n) - where n is the total number of elements in the 2D array
+ Space: O(n)
+ */
+
+/// Iterative Spiral Matrix traversal
+/// - Parameter array: 2D input array
+/// - Returns: One-dimensional result array
+func spiralTraverseIterative(array: [[Int]]) -> [Int] {
+    if array.count == 0 { return [] }
+    
+    var result = [Int]()
+    
+    var startRow = 0
+    var startCol = 0
+    var endRow = array.count - 1
+    var endCol = array[0].count - 1
+    
+    while startRow <= endRow, startCol <= endCol {
+        for col in stride(from: startCol, through: endCol, by: 1) {
+            result.append(array[startRow][col])
+        }
+        
+        for row in stride(from: startRow + 1, through: endRow, by: 1) {
+            result.append(array[row][endCol])
+        }
+        
+        for col in stride(from: endCol - 1, through: startCol, by: -1) {
+            if startRow == endRow { break }
+            result.append(array[endRow][col])
+        }
+        
+        for row in stride(from: endRow - 1, through: startCol + 1, by: -1) {
+            if startCol == endCol { break }
+            result.append(array[row][startCol])
+        }
+        
+        startRow += 1
+        endRow -= 1
+        startCol += 1
+        endCol -=  1
+    }
+    
+    return result
+}
+
+
+/// Recursive Spiral Matrix traversal
+/// - Parameter array: 2D array
+/// - Returns: One-dimensional array of all elements from the 2D array traversed in spiral order.
+func spiralTraverseRecursive(array: [[Int]]) -> [Int] {
+    var result = [Int]()
+    spiralHelper(array, 0, array.count - 1, 0, array[0].count - 1, &result)
+    return result
+}
+
+/// Spiral traversal helper function
+/// - Parameters:
+///   - array: 2D array
+///   - startRow: Index of starting row
+///   - endRow: Index of last row
+///   - startCol: Index of first column
+///   - endCol: index of last column
+///   - result: One-dimensional result array.
+func spiralHelper(_ array: [[Int]], _ startRow: Int, _ endRow: Int, _ startCol: Int, _ endCol: Int, _ result: inout [Int]) {
+    if startRow > endRow || startCol > endCol {
+        return
+    }
+    
+    for col in stride(from: startCol, through: endCol, by: 1) {
+        result.append(array[startRow][col])
+    }
+    
+    for row in stride(from: startRow + 1, through: endRow, by: 1) {
+        result.append(array[row][endCol])
+    }
+    
+    for col in stride(from: endCol - 1, through: startCol, by: -1) {
+        if startRow == endRow { break }
+        result.append(array[endRow][col])
+    }
+    
+    for row in stride(from: endRow - 1, through: startRow + 1, by: -1) {
+        if startCol == endCol { break }
+        result.append(array[row][startCol])
+    }
+    
+    spiralHelper(array, startRow + 1, endRow - 1, startCol + 1, endCol - 1, &result)
+}
+
+
+///Test
+let array = [
+    [1,2,3,4],
+    [12,13,14,5],
+    [11,16,15,6],
+    [10,9,8,7]
+]
+spiralTraverseIterative(array: array)
+spiralTraverseRecursive(array: array)
diff --git a/Spiral Matrix/spiral-matrix.playground/contents.xcplayground b/Spiral Matrix/spiral-matrix.playground/contents.xcplayground
new file mode 100644
index 000000000..5da2641c9
--- /dev/null
+++ b/Spiral Matrix/spiral-matrix.playground/contents.xcplayground	
@@ -0,0 +1,4 @@
+<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
+<playground version='5.0' target-platform='ios'>
+    <timeline fileName='timeline.xctimeline'/>
+</playground>
\ No newline at end of file
diff --git a/Spiral Matrix/spiral-matrix.playground/playground.xcworkspace/contents.xcworkspacedata b/Spiral Matrix/spiral-matrix.playground/playground.xcworkspace/contents.xcworkspacedata
new file mode 100644
index 000000000..02642af82
--- /dev/null
+++ b/Spiral Matrix/spiral-matrix.playground/playground.xcworkspace/contents.xcworkspacedata	
@@ -0,0 +1,7 @@
+<?xml version="1.0" encoding="UTF-8"?>
+<Workspace
+   version = "1.0">
+   <FileRef
+      location = "self:/Users/azharanwar/Desktop/swift-interview-algorithms/arrays/spiral-matrix.playground">
+   </FileRef>
+</Workspace>
diff --git a/Spiral Matrix/spiral-matrix.playground/playground.xcworkspace/xcshareddata/IDEWorkspaceChecks.plist b/Spiral Matrix/spiral-matrix.playground/playground.xcworkspace/xcshareddata/IDEWorkspaceChecks.plist
new file mode 100644
index 000000000..18d981003
--- /dev/null
+++ b/Spiral Matrix/spiral-matrix.playground/playground.xcworkspace/xcshareddata/IDEWorkspaceChecks.plist	
@@ -0,0 +1,8 @@
+<?xml version="1.0" encoding="UTF-8"?>
+<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
+<plist version="1.0">
+<dict>
+	<key>IDEDidComputeMac32BitWarning</key>
+	<true/>
+</dict>
+</plist>

From 51499df9eff722106fabd397a3c3afc509bd9d75 Mon Sep 17 00:00:00 2001
From: Azhar Anwar <azharcodes@gmail.com>
Date: Wed, 29 Apr 2020 18:28:21 +0530
Subject: [PATCH 2/5] Update README.markdown

---
 Spiral Matrix/README.markdown | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/Spiral Matrix/README.markdown b/Spiral Matrix/README.markdown
index 495114b65..85f4b81ad 100644
--- a/Spiral Matrix/README.markdown	
+++ b/Spiral Matrix/README.markdown	
@@ -7,7 +7,7 @@ Given a 2D array, which can be a square array with `n == m`,  we want to return
 
 Spiral order will start at the top left corner of the 2D array move all the way to the right-most column on that row, then continue in a spiral pattern all the way until every element has been visited.
 
-// image
+![spiral-matrix](Images/spiral-matrix.jpg)
 
 ## Example
 Given the 2D array

From ac456ece7c824554c3d4f16b7d2b77d5a18ba3f6 Mon Sep 17 00:00:00 2001
From: Azhar Anwar <azharcodes@gmail.com>
Date: Wed, 29 Apr 2020 18:33:52 +0530
Subject: [PATCH 3/5] add: by line

---
 Spiral Matrix/README.markdown | 2 ++
 1 file changed, 2 insertions(+)

diff --git a/Spiral Matrix/README.markdown b/Spiral Matrix/README.markdown
index 85f4b81ad..211acb6ee 100644
--- a/Spiral Matrix/README.markdown	
+++ b/Spiral Matrix/README.markdown	
@@ -152,3 +152,5 @@ spiralTraverse(array: array)
 
 * Time: `O(n)` - where `n` is the total number of elements in the 2D array
 * Space: `O(n)` - since we are storing every element of the 2D array into a one-dimensional array
+---
+Written for Swift Algorithm Club by Azhar Anwar

From 0fc15ddc0d6846f21d6455fffd5aa4e458673e12 Mon Sep 17 00:00:00 2001
From: Azhar Anwar <azharcodes@gmail.com>
Date: Wed, 29 Apr 2020 18:35:52 +0530
Subject: [PATCH 4/5] Update README.markdown

---
 Spiral Matrix/README.markdown | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/Spiral Matrix/README.markdown b/Spiral Matrix/README.markdown
index 211acb6ee..8b674e684 100644
--- a/Spiral Matrix/README.markdown	
+++ b/Spiral Matrix/README.markdown	
@@ -1,6 +1,6 @@
 
 ## Goal
-Traverse a 2D array in Spiral order.
+Traverse a 2D array in spiral order.
 
 ## Overview
 Given a 2D array, which can be a square array with `n == m`,  we want to return a one-dimensional array of all the elements of the 2D array in spiral order.

From 65f3df978df5f44c6ada74bf0ad0d9fa25dd7678 Mon Sep 17 00:00:00 2001
From: Azhar Anwar <azharcodes@gmail.com>
Date: Wed, 29 Apr 2020 21:47:24 +0530
Subject: [PATCH 5/5] Update README.markdown

---
 Spiral Matrix/README.markdown | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/Spiral Matrix/README.markdown b/Spiral Matrix/README.markdown
index 8b674e684..002b8e30c 100644
--- a/Spiral Matrix/README.markdown	
+++ b/Spiral Matrix/README.markdown	
@@ -1,6 +1,6 @@
+# Spiral Matrix
 
-## Goal
-Traverse a 2D array in spiral order.
+Goal: Traverse a 2D array in spiral order.
 
 ## Overview
 Given a 2D array, which can be a square array with `n == m`,  we want to return a one-dimensional array of all the elements of the 2D array in spiral order.