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Diff for: ‎1 Introduction/Arithmetic Operators.py

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if __name__ == '__main__':
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a = int(input())
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b = int(input())
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print(a+b)
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print(a-b)
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print(a*b)
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"""
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Editorial by DOSHI
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We can solve this problem by using basic arithmetic operators like +, - and *.
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Tested by DOSHI
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Problem Tester's code:
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Python 2
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a = int(raw_input())
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b = int(raw_input())
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print a + b
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print a - b
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print a * b
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Python 3
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a = int(input())
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b = int(input())
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print(a + b)
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print(a - b)
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print(a * b)
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"""

Diff for: ‎1 Introduction/Loops.py

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if __name__ == '__main__':
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n = int(input())
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for i in range (n):
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print(i*i)
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"""
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Editorial by DOSHI
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Use loops to iterate over the range.
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Tested by DOSHI
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Problem Tester's code:
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for i in range(int(raw_input())):
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print i**2
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"""

Diff for: ‎1 Introduction/Print Function.py

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if __name__ == '__main__':
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n = int(input())
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for i in range(n):
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print (i+1, end='')
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"""
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Editorial by DOSHI
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Using the map() and the print _function, we can solve this in one line.
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Set by shashank21j
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Problem Setter's code:
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Python 2
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from __future__ import print_function
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print(*range(1, input() + 1), sep="")
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Python 3
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print(*range(1, int(input()) + 1), sep="")
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Tested by DOSHI
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Problem Tester's code:
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Python 2
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from __future__ import print_function
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map(lambda x: print(x + 1,end=''), range(input()))
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Python 3
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list(map(lambda x:print(x + 1, end=''), range(int(input()))))
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"""

Diff for: ‎1 Introduction/Python If-Else.py

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#!/bin/python3
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import math
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import os
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import random
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import re
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import sys
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if __name__ == '__main__':
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n = int(input().strip())
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if((n%2==1) or ( n%2 == 0 and n >= 6 and n <= 20 )):
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print("Weird")
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elif((n>=2 and n <= 5) or (n>20) ):
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print("Not Weird")
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"""
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Set by shashank21j
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Problem Setter's code:
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Python 2
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n = int(raw_input())
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if n % 2 == 1:
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print "Weird"
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elif n % 2 == 0 and 2 <= n <= 5:
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print "Not Weird"
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elif n % 2 == 0 and 6 <= n <= 20:
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print "Weird"
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else:
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print "Not Weird"
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Python 3
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n = int(input())
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if n % 2 == 1:
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print("Weird")
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elif n % 2 == 0 and 2 <= n <= 5:
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print("Not Weird")
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elif n % 2 == 0 and 6 <= n <= 20:
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print("Weird")
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else:
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print("Not Weird")
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"""

Diff for: ‎1 Introduction/Python- Division.py

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if __name__ == '__main__':
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a = int(input())
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b = int(input())
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print(int(a/b))
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print(float(a/b))
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"""
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Editorial by DOSHI
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In Python 2, __future__ module includes a new type of division called integer division given by the operator //
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Now / performs float division and // performs integer division.
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Tested by DOSHI
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Problem Tester's code:
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Python 2
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from __future__ import division
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a = int(raw_input())
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b = int(raw_input())
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print a // b
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print a / b
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Python 3
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a = int(input())
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b = int(input())
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print(a // b)
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print(a / b)
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"""

Diff for: ‎1 Introduction/Say Hello, World! With Python.py

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print("Hello, World!")
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"""
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Editorial by DOSHI
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Use print to write the resulting object to standard output.
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Python 2
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print "Hello, World!"
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Python 3
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print("Hello, World!")
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"""

Diff for: ‎1 Introduction/Write a function.py

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def is_leap(year):
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leap = False
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# Write your logic here
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if((year%400 == 0) or ( year%4 == 0 and year%100 != 0)):
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leap= True
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return leap
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"""
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Editorial by shashank21j
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Just implement a function using def and if-else logic.
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Solutions
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Python 2
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def is_leap(n):
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if n % 400 == 0:
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return True
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if n % 100 == 0:
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return False
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if n % 4 == 0:
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return True
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return False
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print is_leap(input())
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Python 3
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def is_leap(n):
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if n % 400 == 0:
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return True
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if n % 100 == 0:
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return False
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if n % 4 == 0:
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return True
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return False
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print(is_leap(int(input())))
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Python 2
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def is_leap(year):
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return (year % 400 == 0) or (( year % 100 != 0) and (year % 4 == 0))
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print is_leap(input())
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"""

Diff for: ‎2 Basic Data Types/Find the Runner-Up Score!.py

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if __name__ == '__main__':
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n = int(input())
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arr = list( map(int, input().split()))
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arr.sort(reverse=True)
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for i in arr:
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if(i<arr[0]):
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print(i)
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break
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"""
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Editorial by shashank21j
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There are many ways to solve this problem.
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This can be solved by maintaining two variables and . Iterate through the list and find the maximum and store it. Iterate again and find the next maximum value by having an if condition that checks if it's not equal to first maximum.
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Create a counter from the given array. Extract the keys, sort them and print the second last element.
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Transform the list to a set and then list again, removing all the duplicates. Then sort the list and print the second last element.
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Set by harsh_beria93
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Problem Setter's code:
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Python 2
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if __name__ == '__main__':
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n = int(raw_input())
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arr = map(int, raw_input().split())
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m1 = max(arr)
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m2 = -9999999999
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for i in range(n):
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if arr[i] != m1 and arr[i] > m2:
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m2 = arr[i]
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print m2
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from collections import Counter
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if __name__ == '__main__':
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n = int(raw_input())
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arr = Counter(map(int, raw_input().split())).keys()
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arr.sort()
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print arr[-2]
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from collections import Counter
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if __name__ == '__main__':
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n = int(raw_input())
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arr = list(set(map(int, raw_input().split())))
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arr.sort()
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print arr[-2]
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"""

Diff for: ‎2 Basic Data Types/Finding the percentage.py

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if __name__ == '__main__':
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n = int(input())
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student_marks = {}
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for _ in range(n):
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name, *line = input().split()
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scores = list(map(float, line))
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student_marks[name] = scores
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query_name = input()
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#print (student_marks[query_name][1])
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result = float(0)
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result = result + student_marks[query_name][0]
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result = result + student_marks[query_name][1]
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result = result + student_marks[query_name][2]
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result = float(result/3.00)
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print("{0:.2f}".format(result))
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"""
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Editorial by DOSHI
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Use a dictionary to store the averages as values and the name as keys.
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Tested by DOSHI
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Problem Tester's code:
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d={}
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for i in range(int(raw_input())):
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line=raw_input().split()
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d[line[0]]=sum(map(float,line[1:]))/3
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print '%.2f' % d[raw_input()]
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"""

Diff for: ‎2 Basic Data Types/List Comprehensions.py

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if __name__ == '__main__':
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x = int(input())
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y = int(input())
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z = int(input())
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n = int(input())
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a = []
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for i in range(x+1):
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for j in range(y+1):
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for k in range(z+1):
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if(i+j+k != n ):
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a.append([i,j,k])
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print(a)
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"""
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Editorial by DOSHI
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List comprehensions are an elegant way where lists can be built without having to use different for loops to append values one by one.
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Solution
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Python 2
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a, b, c, n = [int(raw_input()) for _ in xrange(4)]
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print [[x,y,z] for x in xrange(a + 1) for y in xrange(b + 1) for z in xrange(c + 1) if x + y + z != n]
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"""

Diff for: ‎2 Basic Data Types/Lists.py

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if __name__ == '__main__':
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n = int(input())
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l = []
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for _ in range(n):
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s = input().split()
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if(s[0]=='insert'):
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a = int(s[1])
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b = int(s[2])
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l.insert(a, b)
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elif(s[0]=='print'):
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print(l)
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elif(s[0]=='remove'):
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a = int(s[1])
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l.remove(a)
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elif(s[0]=='append'):
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a = int(s[1])
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l.append(a)
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elif(s[0]=='sort'):
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l.sort()
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elif(s[0]=='pop'):
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l.pop()
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elif(s[0]=='reverse'):
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l.reverse()
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"""
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Editorial by DOSHI
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We can solve this using list methods and conditionals.
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Tested by DOSHI
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Problem Tester's code:
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arr = []
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for i in range(int(raw_input())):
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s = raw_input().split()
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for i in range(1,len(s)):
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s[i] = int(s[i])
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if s[0] == "append":
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arr.append(s[1])
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elif s[0] == "extend":
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arr.extend(s[1:])
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elif s[0] == "insert":
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arr.insert(s[1],s[2])
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elif s[0] == "remove":
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arr.remove(s[1])
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elif s[0] == "pop":
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arr.pop()
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elif s[0] == "index":
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print arr.index(s[1])
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elif s[0] == "count":
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print arr.count(s[1])
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elif s[0] == "sort":
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arr.sort()
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elif s[0] == "reverse":
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arr.reverse()
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elif s[0] == "print":
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print arr
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"""

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