Make null produce an IntrinsicNode

Author: michaldudak

src/parsers/typeResolver.ts

@@ -165,10 +165,14 @@ export function resolveType(
 			return new IntrinsicNode('undefined');
 		}
 
-		if (type.flags & ts.TypeFlags.Any || type.flags & ts.TypeFlags.Unknown) {
+		if (type.flags & ts.TypeFlags.Any) {
 			return new IntrinsicNode('any');
 		}
 
+		if (type.flags & ts.TypeFlags.Unknown) {
+			return new IntrinsicNode('unknown');
+		}
+
 		if (type.flags & ts.TypeFlags.Literal) {
 			if (type.isLiteral()) {
 				return new LiteralNode(
@@ -180,7 +184,7 @@ export function resolveType(
 		}
 
 		if (type.flags & ts.TypeFlags.Null) {
-			return new LiteralNode('null');
+			return new IntrinsicNode('null');
 		}
 
 		// TODO: currently types can be either a "function" or an "object" but not both.

test/props-literals/output.json

@@ -34,8 +34,8 @@
 					{
 						"name": "nullLiteral",
 						"type": {
-							"kind": "literal",
-							"value": "null"
+							"kind": "intrinsic",
+							"name": "null"
 						},
 						"optional": false
 					}

test/react-refs/output.json

@@ -70,10 +70,6 @@
 						"type": {
 							"kind": "union",
 							"types": [
-								{
-									"kind": "literal",
-									"value": "null"
-								},
 								{
 									"kind": "reference",
 									"name": "RefCallback"
@@ -82,6 +78,10 @@
 									"kind": "reference",
 									"name": "RefObject"
 								},
+								{
+									"kind": "intrinsic",
+									"name": "null"
+								},
 								{
 									"kind": "intrinsic",
 									"name": "undefined"

test/simple-types/output.json

@@ -34,8 +34,8 @@
 					{
 						"name": "n",
 						"type": {
-							"kind": "literal",
-							"value": "null"
+							"kind": "intrinsic",
+							"name": "null"
 						},
 						"optional": false
 					}