Merge pull request #1027 from wiobber/luadeploysp25

bartsnapp · web-flow · commit a795044c4db6 · 2025-02-10T15:34:03.000-05:00
try to compile with v2.5.10
diff --git a/.github/workflows/serve-ximera.yml b/.github/workflows/serve-ximera.yml
@@ -0,0 +1,96 @@
+name: Ximera Workflow
+
+on:
+  push:      
+
+jobs:
+  build-ximera:
+    name: Build and preview Ximera Courses
+    runs-on: ubuntu-latest
+
+    permissions:
+      actions: read
+      contents: read
+      packages: write
+
+    steps:
+      - name: Checkout code
+        uses: actions/checkout@v4
+        with:
+          fetch-depth: 0   # full 
+
+      - name: Setup cache
+        uses: actions/cache@v4
+        with:
+          path: | 
+            **/*.html
+            **/*.pdf
+            **/*.svg
+            **/*.aux
+            **/*.xref
+            **/*.toc
+            !xmPictures/**
+            !.git/**
+            !.github/**
+          key: ximera-${{ github.ref_name }}-${{ github.sha }}
+          restore-keys: |
+            ximera-${{ github.ref_name }}-
+            ximera-
+
+
+      - name: Build and publish Ximera courses
+        env:
+          GPG_KEY: ${{ secrets.GPG_KEY }}
+          GPG_KEY_ID: ${{ secrets.GPG_KEY_ID }}
+          XIMERA_URL: ${{ vars.XIMERA_URL }}
+          XIMERA_NAME: ${{ vars.XIMERA_NAME }}${{ github.ref_name }}
+        run: |
+          ls -alrt
+          # git config --global --add safe.directory "$(pwd)"
+          # export COMMAND=./xmScripts/xmlatex.test
+          # ./xmScripts/xmlatex ghaction calculus*.tex || echo NOK 
+          ./xmScripts/xmlatex ghaction  --compile draft.html || echo NOK 
+          echo "✅ Published to $XIMERA_URL$XIMERA_NAME " >> $GITHUB_STEP_SUMMARY
+
+      - name: Setup ximera serve cache (only .git)
+        id: serve-cache
+        uses: actions/cache/save@v4
+        with:
+          path: | 
+            xmScripts/**
+            .git/**
+          key: ximeraSERVE-${{ github.ref_name }}-${{ github.sha }}
+
+
+  publish-ximera:
+    name: Publish Ximera Courses
+    needs: build-ximera # Waits for the build job to complete
+    runs-on: ubuntu-latest
+    environment: production
+    steps:
+
+
+      - name: Restore ximera serve cache (only .git)
+        id: serve-cache-restore
+        uses: actions/cache/restore@v4
+        with:
+          fail-on-cache-miss: true
+          path: | 
+            xmScripts/**
+            .git/**
+          key: ximeraSERVE-${{ github.ref_name }}-${{ github.sha }}
+          
+      - name: Serve
+        env:
+          GPG_KEY: ${{ secrets.GPG_KEY }}
+          GPG_KEY_ID: ${{ secrets.GPG_KEY_ID }}
+          XIMERA_URL: ${{ vars.XIMERA_URL }}
+          XIMERA_NAME: ${{ vars.XIMERA_NAME }}
+        run: |
+          ./xmScripts/xmlatex name         
+          ./xmScripts/xmlatex serve -f --compile draft.html # NOTE: -f  should not be needed ...        
+          # ./xmScripts/xmlatex serve calculus*.tex -f  # NOTE: -f  should not be needed ...        
+          echo "✅ Published to $XIMERA_URL$XIMERA_NAME " >> $GITHUB_STEP_SUMMARY
+
+
+
diff --git a/antiderivatives/digInBasicAntiderivatives.tex b/antiderivatives/digInBasicAntiderivatives.tex
@@ -559,7 +559,7 @@ \section{Differential equations}
 \end{question}
 \begin{remark}
     We can directly check that any function $f(x)=Ce^x$ is a solution to our differential equation $f'(x)=f(x)$. Could there be any others? It turns out that these are the \textit{only} solutions. But showing that we didn't miss any is a bit tricky.
-    \begin{expandable}
+    \begin{expandable}{explanation}{}
    \begin{explanation}
     Well, suppose we have some mysterious function $f$ and all we know is that $f'(x)=f(x)$. Let's define a new function $g(x)=f(x)/e^x$. Since our denominator is never 0, the quotient rule tells us that
     \[
diff --git a/computationsForGraphingFunctions/breakGround.tex b/computationsForGraphingFunctions/breakGround.tex
@@ -56,7 +56,7 @@
        \item Compute $f'$ and $f''$.
   \item Analyze end behavior:  as $x \to \pm \infty$, what happens to the graph of $f$?  Does it  have horizontal asymptotes, increase or decrease without bound, or have some other kind of behavior?
  \end{enumerate}
-   \item Use either the first or second derivative test to identify local extrema and/or
+  Use either the first or second derivative test to identify local extrema and/or
     find the intervals where your function is increasing/decreasing.
   In what order should we take these steps? For example, one must compute
    $f'$ before computing $f''$. Also, one must compute $f'$ before 
diff --git a/continuityOfFunctionsOfSeveralVariables/digInContinuity.tex b/continuityOfFunctionsOfSeveralVariables/digInContinuity.tex
@@ -103,7 +103,7 @@
     \]
     A set that is not bounded is \dfn{unbounded}.
   \end{itemize}
-  \item Given a set $S$, we denote the \dfn{boundary} of $S$ by
+  Given a set $S$, we denote the \dfn{boundary} of $S$ by
     $\partial S$.
 \end{definition}
 
diff --git a/coverArt/calculus1Cover/starsRed.xbb b/coverArt/calculus1Cover/starsRed.xbb
@@ -0,0 +1,6 @@
+%%Title: coverArt/calculus1Cover/starsRed.jpg
+%%Creator: extractbb 20240407
+%%BoundingBox: 0 0 5184 3456
+%%HiResBoundingBox: 0.000000 0.000000 5184.000000 3456.000000
+%%CreationDate: Thu Feb  6 21:02:28 2025
+
diff --git a/coverArt/calculus2Cover/starsBlue.xbb b/coverArt/calculus2Cover/starsBlue.xbb
@@ -0,0 +1,6 @@
+%%Title: coverArt/calculus2Cover/starsBlue.jpg
+%%Creator: extractbb 20240407
+%%BoundingBox: 0 0 5184 3456
+%%HiResBoundingBox: 0.000000 0.000000 5184.000000 3456.000000
+%%CreationDate: Thu Feb  6 21:02:28 2025
+
diff --git a/coverArt/calculus3Cover/starsTurquoise.xbb b/coverArt/calculus3Cover/starsTurquoise.xbb
@@ -0,0 +1,6 @@
+%%Title: coverArt/calculus3Cover/starsTurquoise.jpg
+%%Creator: extractbb 20240407
+%%BoundingBox: 0 0 5184 3456
+%%HiResBoundingBox: 0.000000 0.000000 5184.000000 3456.000000
+%%CreationDate: Thu Feb  6 21:02:28 2025
+
diff --git a/coverArt/calculusA2Cover/starsGreen.xbb b/coverArt/calculusA2Cover/starsGreen.xbb
@@ -0,0 +1,6 @@
+%%Title: coverArt/calculusA2Cover/starsGreen.jpg
+%%Creator: extractbb 20240407
+%%BoundingBox: 0 0 5184 3456
+%%HiResBoundingBox: 0.000000 0.000000 5184.000000 3456.000000
+%%CreationDate: Thu Feb  6 21:02:28 2025
+
diff --git a/coverArt/calculusECover/starsAmber.xbb b/coverArt/calculusECover/starsAmber.xbb
@@ -0,0 +1,6 @@
+%%Title: coverArt/calculusECover/starsAmber.jpg
+%%Creator: extractbb 20240407
+%%BoundingBox: 0 0 5184 3456
+%%HiResBoundingBox: 0.000000 0.000000 5184.000000 3456.000000
+%%CreationDate: Thu Feb  6 21:02:28 2025
+
diff --git a/definitionOfTheDerivative/exercises/averageVelocityInterval1.tex b/definitionOfTheDerivative/exercises/averageVelocityInterval1.tex
@@ -50,9 +50,9 @@
 \begin{exercise}
 
 The average velocity of the object on the interval $[0,2]$ is
-\[
+$$
 v_{\text{av}} = \answer{0}\text{m/s.}
-\]
+$$
 \end{exercise}
 \end{exercise}
 
diff --git a/definitionOfTheDerivative/exercises/secantLineTangentLine1.tex b/definitionOfTheDerivative/exercises/secantLineTangentLine1.tex
@@ -11,9 +11,9 @@
 \begin{exercise}
 
 An object is moving along a horizontal line.  Its position in feet is given by
-\[
+$$
 s(t) = t^2 - 2
-\]
+$$
 where $0\leq t\leq 5$ is in seconds.
 
 Consider the points on the line below.
@@ -47,26 +47,26 @@
 \begin{exercise}
 
 The average velocity of the object on the interval $[1,3]$ is
-\[
+$$
 v_{\text{av}} = \answer{4}\text{ft/s.}
-\]
+$$
 
 The average velocity of the object on the interval $[1,t]$ for $t>1$ is
-\[
+$$
 v_{\text{av}} = \answer{t+1}\text{ft/s.}
-\]
+$$
 
 The average velocity of the object on the interval $[t,1]$ for $0<t<1$ is
-\[
+$$
 v_{\text{av}} = \answer{t+1}\text{ft/s.}
-\]
+$$
 
 \begin{exercise}
 
 The instantaneous velocity of the object at $t=1$ is
-\[
+$$
 v_{\text{inst}} = \answer{2}\text{ft/s.}
-\]
+$$
 
 \begin{exercise}
 
@@ -94,9 +94,9 @@
 \end{tikzpicture}
 
 Assume that $P$ and $A$ are points on the graph of $s(t)$.  Then
-\[
+$$
 P = \left(1,\answer{-1}\right) \text{ and } A = \left(t,\answer{t^2-2}\right).
-\]
+$$
 
 \begin{exercise}
 
@@ -132,9 +132,9 @@
 \end{tikzpicture}
 
 The slope of this secant line for $0<t<1$ is
-\[
+$$
 m_{\text{sec}} = \answer{\frac{1-t^2}{1-t}}.
-\]
+$$
 
 What is the connection between the slope of this secant line and the average velocity of the object over the interval $[t,1]$?
 
@@ -176,9 +176,9 @@
 \end{tikzpicture}
 
 The slope of the tangent line above is
-\[
+$$
 m_{\text{tan}} = \answer{2}.
-\]
+$$
 
 
 \end{exercise}
diff --git a/greensTheorem/digInCurlAndGreensTheorem.tex b/greensTheorem/digInCurlAndGreensTheorem.tex
@@ -18,6 +18,8 @@
 \end{abstract}
 \maketitle
 
+\renewcommand{\d}{\,d}
+
 %\begin{strip}
 A fundamental object in calculus is the derivative. However, there are
 different derivatives for different types of functions, an in each
diff --git a/logos/authorGuideLogo/bwstars.xbb b/logos/authorGuideLogo/bwstars.xbb
@@ -0,0 +1,6 @@
+%%Title: logos/authorGuideLogo/bwstars.jpg
+%%Creator: extractbb 20240407
+%%BoundingBox: 0 0 5184 3456
+%%HiResBoundingBox: 0.000000 0.000000 5184.000000 3456.000000
+%%CreationDate: Thu Feb  6 21:02:28 2025
+
diff --git a/outcomesList/outcomesBySection.tex b/outcomesList/outcomesBySection.tex
@@ -41,6 +41,8 @@
 
 
 %% Allows for a wide text/regular text
+\providecommand{\fullwidth}{}
+\providecommand{\normalwidth}{}
 \renewcommand{\fullwidth}{\newgeometry{textwidth=10cm,textheight=10cm}}
 \renewcommand{\normalwidth}{\restoregeometry}
 %% End
@@ -174,8 +176,9 @@
 \masterinput{../appliedOptimization/titlePage.tex}
 
 
-%% Derivatives of trigonometric functions
-\masterinput{../trigonometricDerivatives/titlePage.tex}
+% 20250210: DOES NOT EXIST ???
+% %% Derivatives of trigonometric functions
+% \masterinput{../trigonometricDerivatives/titlePage.tex}
 
 %% Implicit differentiation
 \masterinput{../implicitDifferentiation/titlePage.tex}
diff --git a/recitation/calculus2/trigonometricSubstitution/trigonometricSubstitution.tex b/recitation/calculus2/trigonometricSubstitution/trigonometricSubstitution.tex
@@ -92,6 +92,7 @@ \section{Discussion Questions}
 \begin{problem}
 Two students are asked to evaluate $\int \sqrt{x^2-4} \d x$.
 
+\begin{itemize}
 \item[I.] One student claims that
 \[
 \int \sqrt{x^2-4} \d x = \int x-2 \d x = \frac{1}{2}x^2 - 2x + C.
@@ -103,6 +104,7 @@ \section{Discussion Questions}
 \int \sqrt{x^2-4} \d x =\int \sqrt{4 \sec^2(\theta)-4} \d \theta = \int \sqrt{4 \tan^2(\theta)} \d \theta =  \int \tan(\theta) \d \theta
 \]
 Is this student's solution correct so far? If not, determine a likely error that the student made in the calculation.
+\end{itemize}
 \end{problem}
 
 \begin{freeResponse}
diff --git a/shapeOfThingsToCome/digInStokesTheorem.tex b/shapeOfThingsToCome/digInStokesTheorem.tex
@@ -12,6 +12,8 @@
 \end{abstract}
 \maketitle
 
+\renewcommand{\d}{\,d}
+
 Our final fundamental theorem of calculus is Stokes'
 theorem. Historically speaking, Stokes' theorem was discovered after
 both Green's theorem and the divergence theorem. Its application is
diff --git a/shapeOfThingsToCome/digInSurfaceIntegrals.tex b/shapeOfThingsToCome/digInSurfaceIntegrals.tex
@@ -392,16 +392,16 @@ \section{Flux: The flow across a surface}
   \addplot3 [
     surf,
     colormap/cool,
-    shader     = faceted interp,
+    %%%% shader     = faceted interp,
     point meta = x,
     samples    = 40,
     samples y  = 5,
     z buffer   = sort,
     domain     = 0:360,
     y domain   =-0.5:0.5
   ] (
-    {(1+0.5*y*cos(x/2)))*cos(x)},
-    {(1+0.5*y*cos(x/2)))*sin(x)},
+    {(1+0.5*y*cos(x/2))*cos(x)},
+    {(1+0.5*y*cos(x/2))*sin(x)},
     {0.5*y*sin(x/2)}
   );
   \end{axis}
diff --git a/xmPreamble.tex b/xmPreamble.tex
@@ -0,0 +1,2 @@
+\def\xmNotExpandableAsAccordion{true}
+\def\xmNotHintAsExpandable{true}
