forked from ngthanhtrung23/CompetitiveProgramming
-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathD.cpp
More file actions
70 lines (57 loc) · 2.05 KB
/
D.cpp
File metadata and controls
70 lines (57 loc) · 2.05 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
#include <bits/stdc++.h>
#define FOR(i,a,b) for(int i=(a),_b=(b); i<=_b; ++i)
#define FORD(i,a,b) for(int i=(a),_b=(b); i>=_b; --i)
#define REP(i,a) for(int i=0,_a=(a); i < _a; ++i)
#define DEBUG(X) { cout << #X << " = " << (X) << endl; }
#define PR(A,n) { cout << #A << " = "; FOR(_,1,n) cout << A[_] << ' '; cout << endl; }
#define PR0(A,n) { cout << #A << " = "; REP(_,n) cout << A[_] << ' '; cout << endl; }
#define sqr(x) ((x) * (x))
#define ll long long
#define __builtin_popcount __builtin_popcountll
#define SZ(x) ((int) (x).size())
using namespace std;
const int MN = 2011;
const int MOD = 1e9 + 7;
int n, a[MN], b[MN], eq[MN][MN], f[MN][MN], g[MN], dp[MN][MN];
void init() {
FOR(i,0,MN-1) FOR(j,0,MN-1) {
if (i == 0 && j == 0) dp[i][j] = 1;
else if (i < j) dp[i][j] = 0;
else {
if (i) dp[i][j] = (dp[i][j] + dp[i-1][j]) % MOD;
if (j) dp[i][j] = (dp[i][j] + dp[i][j-1]) % MOD;
}
}
FOR(i,0,MN-1) g[i] = dp[i][i];
}
int main() {
ios :: sync_with_stdio(0); cin.tie(0);
cout << (fixed) << setprecision(9);
init();
while (scanf("%d", &n) == 1) {
FOR(i,1,n) scanf("%d", &a[i]);
FOR(i,1,n) scanf("%d", &b[i]);
FOR(i,1,n) FOR(j,1,n) {
eq[i][j] = (a[i] == b[j]) ? eq[i-1][j-1] + 1 : 0;
}
memset(f, 0, sizeof f);
FOR(i,0,n) f[i][0] = f[0][i] = 1;
FOR(i,1,n) FOR(j,1,n) {
if (a[i] != b[j]) {
f[i][j] = (f[i-1][j] + f[i][j-1]) % MOD;
}
else {
int u = eq[i][j];
if (i == u && j == u)
f[i][j] = f[i-u][j-u] * (ll) g[u] % MOD;
FOR(k,0,u) {
if (j > u)
f[i][j] = (f[i][j] + f[i-k][j-u-1] * (ll) dp[u][k]) % MOD;
if (i > u)
f[i][j] = (f[i][j] + f[i-u-1][j-k] * (ll) dp[u][k]) % MOD;
}
}
}
cout << f[n][n] << endl;
}
}