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F.cpp
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126 lines (103 loc) · 3.01 KB
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#include <bits/stdc++.h>
#define int long long
#define FOR(i,a,b) for(int i=(a),_b=(b); i<=_b; ++i)
#define FORD(i,a,b) for(int i=(a),_b=(b); i>=_b; --i)
#define REP(i,a) for(int i=0,_a=(a); i < _a; ++i)
#define sqr(x) ((x) * (x))
#define ll long long
#define __builtin_popcount __builtin_popcountll
#define SZ(x) ((int) (x).size())
using namespace std;
const int MN = 1011;
int m, n, k;
int a[MN][MN], id[MN][MN];
int lab[MN*MN];
struct DSU {
void init(int n) {
REP(i,n+1) lab[i] = -1;
}
int getRoot(int u) {
if (lab[u] < 0) return u;
return lab[u] = getRoot(lab[u]);
}
bool merge(int u, int v) {
u = getRoot(u); v = getRoot(v);
if (u == v) return false;
if (lab[u] > lab[v]) swap(u, v);
lab[u] += lab[v];
lab[v] = u;
return true;
}
};
pair<int, pair<int,int> > all[MN * MN];
int can[MN][MN];
const int di[4] = {-1,1,0,0};
const int dj[4] = {0,0,-1,1};
DSU dsu;
void enable(int u, int v) {
can[u][v] = 1;
REP(dir,4) {
int uu = u + di[dir], vv = v + dj[dir];
if (can[uu][vv]) {
dsu.merge(id[uu][vv], id[u][v]);
}
}
}
int visited[MN][MN];
int qu[MN * MN], qv[MN * MN], first, last;
void bfs(int u, int v, int need) {
first = last = 1;
qu[1] = u; qv[1] = v;
visited[u][v] = 1;
if (need == 1) return ;
while (first <= last) {
int u = qu[first], v = qv[first]; ++first;
REP(dir,4) {
int uu = u + di[dir], vv = v + dj[dir];
if (can[uu][vv] && !visited[uu][vv]) {
++last;
qu[last] = uu;
qv[last] = vv;
visited[uu][vv] = 1;
if (last == need) {
return ;
}
}
}
}
}
#undef int
int main() {
#define int long long
while (scanf("%lld%lld%lld", &m, &n, &k) == 3) {
FOR(i,1,m) FOR(j,1,n) scanf("%lld", &a[i][j]);
int cnt = 0;
FOR(i,1,m) FOR(j,1,n) {
id[i][j] = ++cnt;
all[cnt] = make_pair(-a[i][j], make_pair(i, j));
}
sort(all+1, all+cnt+1);
dsu.init(cnt);
memset(can, 0, sizeof can);
bool good = false;
FOR(i,1,cnt) {
int u = all[i].second.first, v = all[i].second.second;
enable(u, v);
if (k % a[u][v] == 0) {
int has = -lab[dsu.getRoot(id[u][v])];
if (has >= k / a[u][v]) {
good = true;
puts("YES");
memset(visited, 0, sizeof visited);
bfs(u, v, k / a[u][v]);
FOR(i,1,m) {
FOR(j,1,n) if (visited[i][j]) printf("%lld ", a[u][v]); else printf("0 ");
puts("");
}
break;
}
}
}
if (!good) puts("NO");
}
}