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E.cpp
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97 lines (88 loc) · 2.9 KB
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#include <bits/stdc++.h>
#define FOR(i,a,b) for(int i=(a),_b=(b); i<=_b; ++i)
#define FORD(i,a,b) for(int i=(a),_b=(b); i>=_b; --i)
#define REP(i,a) for(int i=0,_a=(a); i < _a; ++i)
#define DEBUG(X) { cout << #X << " = " << (X) << endl; }
#define PR(A,n) { cout << #A << " = "; FOR(_,1,n) cout << A[_] << ' '; cout << endl; }
#define PR0(A,n) { cout << #A << " = "; REP(_,n) cout << A[_] << ' '; cout << endl; }
#define sqr(x) ((x) * (x))
#define ll long long
#define __builtin_popcount __builtin_popcountll
#define SZ(x) ((int) (x).size())
using namespace std;
double safe_sqrt(double x) {
return sqrt(max((double) 0.0,x));
}
int GI(ll& x) {
return scanf("%lld", &x);
}
const int MN = 500111;
const int MAX = 36;
double f[MN][MAX + 5], newf[MN][MAX+5];
int father[MN];
int main() {
ios :: sync_with_stdio(0); cin.tie(0);
cout << (fixed) << setprecision(3);
// double res = 0.0;
// FOR(i,40,500000) {
// res += (i - 1) * pow((double) 0.5, i-1);
// }
// DEBUG(res);
int q;
while (scanf("%d", &q) == 1) {
memset(father, 0, sizeof father);
memset(f, 0.0, sizeof f);
REP(i,MAX) f[1][i] = 1.0;
int n = 1;
FOR(i,1,q) {
int typ; scanf("%d", &typ);
int u; scanf("%d", &u);
if (typ == 1) {
++n;
father[n] = u;
REP(i,MAX) f[n][i] = 1.0;
int v;
v = n; u = father[n];
// calculate newf
REP(up,MAX) {
REP(h,MAX) {
newf[u][h] = f[u][h];
if (v == n) {
if (h == 0) newf[u][h] *= 0.5;
else newf[u][h] *= 0.5 * (1 + f[v][h-1]);
}
else {
if (h == 0) {
} else {
newf[u][h] /= 0.5 * (1 + f[v][h-1]);
newf[u][h] *= 0.5 * (1 + newf[v][h-1]);
}
}
}
v = u;
u = father[u];
if (!u) break;
}
// update f
v = n; u = father[n];
REP(up,MAX) {
REP(h,MAX) {
f[u][h] = newf[u][h];
}
v = u;
u = father[u];
if (!u) break;
}
}
else {
double last = 0.0;
double res = 0.0;
REP(h,MAX) {
res += h * (f[u][h] - last);
last = f[u][h];
}
printf("%.9f\n", (double) res);
}
}
}
}