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| 1 | +package codechallenge.linkedlist; |
| 2 | + |
| 3 | +import me.premaseem.reusable.MyDLLNode; |
| 4 | +import org.junit.Test; |
| 5 | + |
| 6 | +/* |
| 7 | +
|
| 8 | +Challenge: Inserting a Node Into a Sorted Doubly Linked List |
| 9 | + 1. Empty list |
| 10 | + 2. At the beginning of the list |
| 11 | + 3. Somewhere at the middle of the list |
| 12 | + 4. At the end of the list |
| 13 | + */ |
| 14 | + |
| 15 | + |
| 16 | +public class InsertNodeInSortedLL { |
| 17 | + |
| 18 | + // Test Driven Development by Aseem Jain |
| 19 | + @Test |
| 20 | + public void test() { |
| 21 | + MyDLLNode n1 = new MyDLLNode(-100); |
| 22 | + MyDLLNode n2 = new MyDLLNode(0); |
| 23 | + MyDLLNode n3 = new MyDLLNode(70); |
| 24 | + MyDLLNode n4 = new MyDLLNode(10000); |
| 25 | + |
| 26 | + n1.next = n2; |
| 27 | + n2.next = n3; |
| 28 | + n3.next = n4; |
| 29 | + |
| 30 | + n4.prev = n3; |
| 31 | + n3.prev = n2; |
| 32 | + n2.prev = n1; |
| 33 | + |
| 34 | + sortedInsert(n1, 250); |
| 35 | + assert n3.next.data == 250; |
| 36 | + assert n4.prev.data == 250; |
| 37 | + |
| 38 | + sortedInsert(n1, 250000); |
| 39 | + assert n4.next.data == 250000; |
| 40 | + |
| 41 | + } |
| 42 | + |
| 43 | + |
| 44 | + // Using Recursion |
| 45 | + MyDLLNode sortedInsertR(MyDLLNode head, int data) { |
| 46 | + if (head == null) { |
| 47 | + return new MyDLLNode(data); |
| 48 | + } else if (data <= head.data) { |
| 49 | + MyDLLNode n = new MyDLLNode(data); |
| 50 | + n.next = head; |
| 51 | + head.prev = n; |
| 52 | + return n; |
| 53 | + } else { |
| 54 | + MyDLLNode rest = sortedInsert(head.next, data); |
| 55 | + head.next = rest; |
| 56 | + rest.prev = head; |
| 57 | + return head; |
| 58 | + } |
| 59 | + } |
| 60 | + |
| 61 | + // Using Greedy algorithm |
| 62 | + MyDLLNode sortedInsert(MyDLLNode head, int data) { |
| 63 | + MyDLLNode nn = new MyDLLNode(data); |
| 64 | + if (head == null) { |
| 65 | + return nn; |
| 66 | + } |
| 67 | + MyDLLNode cn = head; |
| 68 | + |
| 69 | + while(cn.next != null && cn.data < data){ |
| 70 | + cn = cn.next; |
| 71 | + } |
| 72 | + |
| 73 | + if(head == cn){ |
| 74 | + nn.next = cn; |
| 75 | + cn.prev = nn; |
| 76 | + return nn; |
| 77 | + } |
| 78 | + |
| 79 | + if(cn.data<data){ |
| 80 | + cn.next = nn; |
| 81 | + nn.prev = cn; |
| 82 | + }else{ |
| 83 | + nn.next = cn; |
| 84 | + nn.prev = cn.prev; |
| 85 | + cn.prev.next = nn; |
| 86 | + cn.prev = nn; |
| 87 | + } |
| 88 | + |
| 89 | + return head; |
| 90 | + |
| 91 | + } |
| 92 | +} |
| 93 | + |
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