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| 1 | +# 练习函数式编程的map和reduce |
| 2 | +from functools import reduce |
| 3 | + |
| 4 | + |
| 5 | +l = [x for x in range(-10, 10, 2)] |
| 6 | +print(l) |
| 7 | +l = list(map(abs, l)) |
| 8 | +print(l) |
| 9 | + |
| 10 | + |
| 11 | +# reduce是将列表做累计运算 |
| 12 | +# lambda是匿名函数 |
| 13 | +num = reduce(lambda x, y: x + y, l) |
| 14 | +print(num) |
| 15 | + |
| 16 | + |
| 17 | +# 将一个字符串转换成整型 |
| 18 | +def str2int(s): |
| 19 | + def char2int(ch): |
| 20 | + c = {str(x): x for x in range(10)} |
| 21 | + return c[ch] |
| 22 | + |
| 23 | + def fun(n1, n2): |
| 24 | + return n1*10 + n2 |
| 25 | + |
| 26 | + return reduce(fun, map(char2int, s)) |
| 27 | + |
| 28 | + |
| 29 | +num = str2int('12345') |
| 30 | +print(type(num), num) |
| 31 | + |
| 32 | + |
| 33 | +# 这是使用匿名函数的简便版 |
| 34 | +def str2int2(s): |
| 35 | + ch = {str(x): x for x in range(10)} |
| 36 | + return reduce(lambda x, y: x*10+y, map(lambda x: ch[x], s)) |
| 37 | + |
| 38 | + |
| 39 | +num = str2int2('12345') |
| 40 | +print(type(num), num) |
| 41 | + |
| 42 | + |
| 43 | +# 作业:利用map()函数,把用户输入的不规范的英文名字,变为首字母大写,其他小写的规范名字 |
| 44 | +def normalize(name): |
| 45 | + # capitalize()函数是将字符串的首字母大写 |
| 46 | + return list(map(lambda x: x.capitalize(), name)) |
| 47 | + |
| 48 | + |
| 49 | +L = ['adam', 'LISA', 'barT'] |
| 50 | +print(normalize(L)) |
| 51 | + |
| 52 | + |
| 53 | +# 作业2:Python提供的sum()函数可以接受一个list并求和,请编写一个prod()函数,可以接受一个list并利用reduce()求积 |
| 54 | +def prod(x, y): |
| 55 | + return x*y |
| 56 | + |
| 57 | + |
| 58 | +num = reduce(prod, [3, 5, 7, 9]) |
| 59 | +print(num) |
| 60 | + |
| 61 | + |
| 62 | +# 作业3:利用map和reduce编写一个str2float函数,把字符串'123.456'转换成浮点数123.456 |
| 63 | +def str2float(s): |
| 64 | + ch = {str(x): x for x in range(10)} |
| 65 | + # 先将字符串分割 |
| 66 | + L = s.split('.') |
| 67 | + # 整数部分 |
| 68 | + n1 = reduce(lambda x, y: x*10 + y, map(lambda x: ch[x], L[0])) |
| 69 | + # 小数部分 |
| 70 | + n2 = reduce(lambda x, y: x * 10 + y, map(lambda x: ch[x], L[1])) |
| 71 | + n2 *= 0.1**len(L[1]) |
| 72 | + return n1+n2 |
| 73 | + |
| 74 | + |
| 75 | +num = str2float('123.456') |
| 76 | +print(num) |
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