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1 1 1 1 1 2 1 1 2 2 1 1 1 1 1 2 2 1 3 1 2 2 2 1 1 3 1 1 1 2 3 1 2 3 1 1 1 1 2 2 1 3 1 1 1 2 1 3 1 1 3 1 1 2 2 1 1 3 1 1 3 2 1 1 1 3 1 1 2 3 1
>>> import itertools >>> seq = [1] >>> for i in range(10): ... print ' '.join(map(str, seq)) ... seq2 = [] ... for key, subgroup in itertools.groupby(seq): ... seq2 += [key, len(list(subgroup))] ... seq = seq2 ...
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