Given an array containing n distinct numbers taken from 0, 1, 2, ..., n
, find the one that is missing from the array.
For example,
Given nums = [0, 1, 3]
return 2
.
Note: Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?
Solution 1
/**
* @param {number[]} nums
* @return {number}
*/
var missingNumber = function(nums) {
"use strict";
let sum = nums.length * (1 + nums.length) / 2;
for (let i = 0; i < nums.length; i++) {
sum -= nums[i];
}
return sum;
};
Solution 2
/**
* Solved with bit manipulation (XOR)
* @param {number[]} nums
* @return {number}
*/
var missingNumber = function(nums) {
"use strict";
let result = 0;
for (let i = 0; i < nums.length; i++) {
result ^= (i ^ nums[i]);
}
result ^= (nums.length);
return result;
};