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So for now I've just use the heat loss survey value converted to per-degree and preheat seems to be within 10% of the actual value which is good enough for me. |
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I'm trying to verify my predheat set up to tune it to be more accurate. The one value I haven't set up yet is the
heat_loss_wattsparameter.The description for this is given in the documentation:
However, I'm struggling to make heads or tails of that description. Would you be able to try and clarify this, perhaps with formulae rather than a block of text.
From what I can tell, I need to find a nice section of heating. I've also calculated
heat_loss_degrees: 0.0366from a 5 hour 'off' period as the house was cooling down.Take for example this - granted only 40min not a full hour, but there is a continuous output power from the heat pump during that period, and the external temperature is pretty stable.
That should from the description be all the information needed, but I'm confused.
Trying to read between the lines there, is the following interpretation correct:
delta_t = (19.8 + 18.4) / 2 - 6.4 = 12.7 *Ctemp_inc = (19.8 - 18.4) = 1.4 *Cstatic_loss = heat_loss_degrees * delta_t * time_hours = 0.0366 * 12.7 * 40/60 = 0.30988(I think that ends up being*C???)energy = 6.2kW * 40/60 = 4.13kWhheat_loss_watts = (temp_inc + static_loss) / delta_t * energy? That comes out askWhunits, so presumably then multiply by40/60as this is a 40 minute window to getheat_loss_watts = (temp_inc + static_loss) / delta_t * energy * time = (1.4 + 0.30988) / 12.7 * 4.13 * 40/60 = 556.5 W.That seems very high to me.
If the figure is meant to be power loss per *C, then based on the heat-loss survey that I had done when the heat pump was installed (actually three different surveys using different tools and metrics giving similar figures), the total loss comes out as 3.91kW at an outside temperature of -3*C. At an average design temperature of 20*C, that gives 3911 / 23 = 170 W/*C which seems more inline with the sample value given.
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