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Copy path1422. Maximum Score After Splitting a String.cpp
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1422. Maximum Score After Splitting a String.cpp
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class Solution {
public:
int maxScore(string s) {
int n = s.size();
vector<int>leftSum(n,0);
vector<int>rightSum(n,0);
if(s[0] == '0'){
leftSum[0] = 1;
}
for(int i = 1; i < n ; i++){
if(s[i] == '0'){
leftSum[i] = leftSum[i-1]+1;
}
else{
leftSum[i] = leftSum[i-1]+0;
}
}
if(s[n-1] == '1'){
rightSum[n-1] = 1;
}
for(int i = n-2; i >= 0 ; i--){
if(s[i] == '1'){
rightSum[i] = rightSum[i+1]+1;
}
else{
rightSum[i] = rightSum[i+1]+0;
}
}
int ans = 0;
for(int i = 0 ; i < n-1 ; i++){
ans = max(ans,leftSum[i]+rightSum[i+1]);
}
return ans;
}
};
class Solution {
public:
int maxScore(string s) {
int n = s.size();
int cnt = 0 , temp = 0, ans = 0;
for(char ch : s){
if(ch == '0'){
cnt++;
}
temp++;
}
if(temp == 0 || cnt == 0) return n-1;
cnt = 0 , temp = 0;
int i = 0 , val = 0;
while(i < n-1){
int k = i;
cnt = 0, temp = 0;
for(int i = 0 ; i <= k ; i++){
if(s[i] == '0')cnt++;
}
for(int j = i+1 ; j < n ; j++){
if(s[j] == '1')temp++;
}
i++;
ans = max(cnt+temp,ans);
}
return ans;
}
};