-
-
Notifications
You must be signed in to change notification settings - Fork 360
[Yiseull] WEEK 10 Solutions #2841
New issue
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
Merged
Merged
Changes from all commits
Commits
Show all changes
2 commits
Select commit
Hold shift + click to select a range
File filter
Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
There are no files selected for viewing
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,22 @@ | ||
| /** | ||
| * Definition for a binary tree node. | ||
| * public class TreeNode { | ||
| * int val; | ||
| * TreeNode left; | ||
| * TreeNode right; | ||
| * TreeNode() {} | ||
| * TreeNode(int val) { this.val = val; } | ||
| * TreeNode(int val, TreeNode left, TreeNode right) { | ||
| * this.val = val; | ||
| * this.left = left; | ||
| * this.right = right; | ||
| * } | ||
| * } | ||
| */ | ||
| class Solution { | ||
| public TreeNode invertTree(TreeNode root) { | ||
| if (root == null) return null; | ||
|
|
||
| return new TreeNode(root.val, invertTree(root.right), invertTree(root.left)); | ||
| } | ||
| } |
|
Contributor
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 🏷️ 알고리즘 패턴 분석search-in-rotated-sorted-array/Yiseull.javaclass Solution {
// 공간복잡도: O(1), 시간복잡도: O(logn)
public int search(int[] nums, int target) {
int left = 0, right = nums.length - 1;
while (left < right) {
int mid = (left + right) / 2;
// 오른쪽 정렬
if (nums[mid] < nums[right]) {
if (nums[mid] <= target && target <= nums[right]) {
if (nums[mid] == target) return mid;
left = mid + 1;
}
else right = mid - 1;
// 왼쪽 정렬
} else {
if (nums[left] <= target && target <= nums[mid]) {
if (nums[mid] == target) return mid;
right = mid - 1;
}
else left = mid + 1;
}
}
return nums[left] == target ? left : -1;
}
}
📊 시간/공간 복잡도 분석
피드백: 루프를 통해 배열의 한쪽이 정렬되었는지 판단하고 해당 구간으로 범위를 좁히며 탐색한다. 개선 제안: 현재 구현이 적절해 보입니다. |
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,28 @@ | ||
| class Solution { | ||
| // 공간복잡도: O(1), 시간복잡도: O(logn) | ||
| public int search(int[] nums, int target) { | ||
| int left = 0, right = nums.length - 1; | ||
|
|
||
| while (left < right) { | ||
| int mid = (left + right) / 2; | ||
|
|
||
| // 오른쪽 정렬 | ||
| if (nums[mid] < nums[right]) { | ||
| if (nums[mid] <= target && target <= nums[right]) { | ||
| if (nums[mid] == target) return mid; | ||
| left = mid + 1; | ||
| } | ||
| else right = mid - 1; | ||
| // 왼쪽 정렬 | ||
| } else { | ||
| if (nums[left] <= target && target <= nums[mid]) { | ||
| if (nums[mid] == target) return mid; | ||
| right = mid - 1; | ||
| } | ||
| else left = mid + 1; | ||
| } | ||
| } | ||
|
|
||
| return nums[left] == target ? left : -1; | ||
| } | ||
| } |
Oops, something went wrong.
Add this suggestion to a batch that can be applied as a single commit.
This suggestion is invalid because no changes were made to the code.
Suggestions cannot be applied while the pull request is closed.
Suggestions cannot be applied while viewing a subset of changes.
Only one suggestion per line can be applied in a batch.
Add this suggestion to a batch that can be applied as a single commit.
Applying suggestions on deleted lines is not supported.
You must change the existing code in this line in order to create a valid suggestion.
Outdated suggestions cannot be applied.
This suggestion has been applied or marked resolved.
Suggestions cannot be applied from pending reviews.
Suggestions cannot be applied on multi-line comments.
Suggestions cannot be applied while the pull request is queued to merge.
Suggestion cannot be applied right now. Please check back later.
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
🏷️ 알고리즘 패턴 분석
invert-binary-tree/Yiseull.java
📊 시간/공간 복잡도 분석
피드백: 트리를 방문하며 각 노드의 좌우 자식을 교환하는 재귀 풀이입니다. 모든 노드를 정확히 한 번 방문하므로 시간 복잡도는 선형입니다.
개선 제안: 현재 구현이 적절해 보입니다.