Skip to content
Open
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
78 changes: 78 additions & 0 deletions sakila_solutions.sql
Original file line number Diff line number Diff line change
@@ -0,0 +1,78 @@
USE sakila;
# 1. Display all available tables in the Sakila database.
SHOW TABLES;

# 2. Retrieve all the data from the tables actor, film and customer.
SELECT * FROM actor;
SELECT * FROM film;
SELECT * FROM customer;

# 3.1 Titles of all films from the film table
SELECT title
FROM film;

# 3.2 List of languages used in films, with the column aliased as language from the language table
SELECT name AS language
FROM language;

# 3.3 List of first names of all employees from the staff table
SELECT first_name
FROM staff;

# 4. Retrieve unique release years
SELECT DISTINCT release_year
FROM film;

# 5. Counting records for database insights:
# 5.1 Determine the number of stores that the company has.
SELECT COUNT(*) AS store_count
FROM store;

# 5.2 Determine the number of employees that the company has.
SELECT COUNT(*) AS employee_count
FROM staff;

# 5.3 Determine how many films are available for rent and how many have been rented.
SELECT
(SELECT COUNT(*) FROM inventory) AS available_for_rent,
(SELECT COUNT(*) FROM rental) AS rented;

# if the question is about finding the films that have been rented from all, at least one time, and not the amount of total rentals:
SELECT COUNT(DISTINCT i.film_id) AS films_rented_at_least_once
FROM rental r
JOIN inventory i ON i.inventory_id = r.inventory_id;

# 5.4 Determine the number of distinct last names of the actors in the database.
SELECT COUNT(DISTINCT last_name) AS distinct_actor_last_names
FROM actor;

# 6. Retrieve the 10 longest films.
SELECT film_id, title, length
FROM film
ORDER BY length DESC, title
LIMIT 10;

# 7. Use filtering techniques in order to:
# 7.1 Retrieve all actors with the first name "SCARLETT".
SELECT *
FROM actor
WHERE first_name = 'SCARLETT';

# BONUS:
# 7.2 Retrieve all movies that have ARMAGEDDON in their title and have a duration longer than 100 minutes.
SELECT film_id, title, length
FROM film
WHERE title LIKE '%ARMAGEDDON%'
AND length > 100;

# 7.3 Determine the number of films that include Behind the Scenes content
SELECT COUNT(*) AS films_with_behind_the_scenes
FROM film
WHERE FIND_IN_SET('Behind the Scenes', special_features) > 0;