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JS: Handle surrogate pairs correctly #69
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Original file line number | Diff line number | Diff line change |
---|---|---|
|
@@ -22,6 +22,16 @@ | |
* @author [email protected] (Neil Fraser) | ||
*/ | ||
|
||
/** | ||
* Determine if the index is inside a surrogate pair. | ||
* @param {string} str The string | ||
* @param {numer} idx The index | ||
*/ | ||
function insideSurrogate(str, idx) { | ||
var code = str.charCodeAt(idx); | ||
return code >= 0xDC00 && code <= 0xDFFF; | ||
} | ||
|
||
/** | ||
* Class containing the diff, match and patch methods. | ||
* @constructor | ||
|
@@ -361,6 +371,11 @@ diff_match_patch.prototype.diff_bisect_ = function(text1, text2, deadline) { | |
x1++; | ||
y1++; | ||
} | ||
if (insideSurrogate(text1, x1)) { | ||
x1--; | ||
y1--; | ||
} | ||
|
||
v1[k1_offset] = x1; | ||
if (x1 > text1_length) { | ||
// Ran off the right of the graph. | ||
|
@@ -569,6 +584,9 @@ diff_match_patch.prototype.diff_commonPrefix = function(text1, text2) { | |
} | ||
pointermid = Math.floor((pointermax - pointermin) / 2 + pointermin); | ||
} | ||
if (insideSurrogate(text1, pointermid)) { | ||
pointermid--; | ||
} | ||
return pointermid; | ||
}; | ||
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||
|
@@ -601,6 +619,9 @@ diff_match_patch.prototype.diff_commonSuffix = function(text1, text2) { | |
} | ||
pointermid = Math.floor((pointermax - pointermin) / 2 + pointermin); | ||
} | ||
if (insideSurrogate(text1, text1.length - pointermid)) { | ||
pointermid--; | ||
} | ||
return pointermid; | ||
}; | ||
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||
|
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I came up with this instead, but I don't have a test that fails in either case so obviously I'm missing a test case
my reasoning was that if the common suffix starts on a low surrogate then we have to bump it to the right so that the surrogate half doesn't end up in the common part - backwards from
commonPrefix
where we want to shift to the left in order to avoid the same for high surrogates