lab-sql-select

solutions-2.sql

@@ -0,0 +1,59 @@
+-- Challenge 1
+SELECT 
+    a.au_id AS "AUTHOR ID",
+    a.au_lname AS "LAST NAME",
+    a.au_fname AS "FIRST NAME",
+    t.title AS "TITLE",
+    p.pub_name AS "PUBLISHER"
+FROM titleauthor ta
+JOIN authors a ON ta.au_id = a.au_id
+JOIN titles t ON ta.title_id = t.title_id
+JOIN publishers p ON t.pub_id = p.pub_id;
+
+-- Challenge 2
+SELECT 
+    a.au_id AS "AUTHOR ID",
+    a.au_lname AS "LAST NAME",
+    a.au_fname AS "FIRST NAME",
+    p.pub_name AS "PUBLISHER",
+    COUNT(t.title_id) AS "TITLE COUNT"
+FROM titleauthor ta
+JOIN authors a ON ta.au_id = a.au_id
+JOIN titles t ON ta.title_id = t.title_id
+JOIN publishers p ON t.pub_id = p.pub_id
+GROUP BY a.au_id, p.pub_name;
+
+-- Challenge 3
+SELECT 
+    a.au_id AS "AUTHOR ID",
+    a.au_lname AS "LAST NAME",
+    a.au_fname AS "FIRST NAME",
+    SUM(s.qty) AS "TOTAL"
+FROM titleauthor ta
+JOIN authors a ON ta.au_id = a.au_id
+JOIN sales s ON ta.title_id = s.title_id
+GROUP BY a.au_id
+ORDER BY "TOTAL" DESC
+LIMIT 3;
+
+-- Challenge 4
+SELECT 
+    a.au_id AS "AUTHOR ID",
+    a.au_lname AS "LAST NAME",
+    a.au_fname AS "FIRST NAME",
+    COALESCE(SUM(s.qty), 0) AS "TOTAL"
+FROM authors a
+LEFT JOIN titleauthor ta ON a.au_id = ta.au_id
+LEFT JOIN sales s ON ta.title_id = s.title_id
+GROUP BY a.au_id
+ORDER BY "TOTAL" DESC;
+SELECT 
+    a.au_id AS "AUTHOR ID",
+    a.au_lname AS "LAST NAME",
+    a.au_fname AS "FIRST NAME",
+    COALESCE(SUM(s.qty), 0) AS "TOTAL"
+FROM authors a
+LEFT JOIN titleauthor ta ON a.au_id = ta.au_id
+LEFT JOIN sales s ON ta.title_id = s.title_id
+GROUP BY a.au_id
+ORDER BY "TOTAL" DESC;