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solution2.sql

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+-- Challenge 1 - Author, Title, Publisher Info
+SELECT a.au_id AS AUTHOR_ID, 
+       a.au_lname AS LAST_NAME, 
+       a.au_fname AS FIRST_NAME, 
+       t.title AS TITLE, 
+       p.pub_name AS PUBLISHER
+FROM authors a
+JOIN titleauthor ta ON a.au_id = ta.au_id
+JOIN titles t ON ta.title_id = t.title_id
+JOIN publishers p ON t.pub_id = p.pub_id;
+
+-- Challenge 2 - Title Count per Author per Publisher
+SELECT a.au_id AS AUTHOR_ID, 
+       a.au_lname AS LAST_NAME, 
+       a.au_fname AS FIRST_NAME, 
+       p.pub_name AS PUBLISHER, 
+       COUNT(t.title_id) AS TITLE_COUNT
+FROM authors a
+JOIN titleauthor ta ON a.au_id = ta.au_id
+JOIN titles t ON ta.title_id = t.title_id
+JOIN publishers p ON t.pub_id = p.pub_id
+GROUP BY a.au_id, a.au_lname, a.au_fname, p.pub_name
+ORDER BY a.au_id, p.pub_name;
+
+-- Challenge 3 - Top 3 Best-Selling Authors
+SELECT a.au_id AS AUTHOR_ID,
+       a.au_lname AS LAST_NAME,
+       a.au_fname AS FIRST_NAME,
+       SUM(s.qty) AS TOTAL
+FROM authors a
+JOIN titleauthor ta ON a.au_id = ta.au_id
+JOIN titles t ON ta.title_id = t.title_id
+JOIN sales s ON t.title_id = s.title_id
+GROUP BY a.au_id, a.au_lname, a.au_fname
+ORDER BY TOTAL DESC
+LIMIT 3;
+
+-- Challenge 4 - Best Selling Authors Ranking (Including Zero Sales)
+SELECT a.au_id AS AUTHOR_ID,
+       a.au_lname AS LAST_NAME,
+       a.au_fname AS FIRST_NAME,
+       COALESCE(SUM(s.qty), 0) AS TOTAL
+FROM authors a
+LEFT JOIN titleauthor ta ON a.au_id = ta.au_id
+LEFT JOIN titles t ON ta.title_id = t.title_id
+LEFT JOIN sales s ON t.title_id = s.title_id
+GROUP BY a.au_id, a.au_lname, a.au_fname
+ORDER BY TOTAL DESC;