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Improved task 2732 #1920

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Feb 25, 2025
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Original file line number Diff line number Diff line change
@@ -1,50 +1,47 @@
package g2701_2800.s2732_find_a_good_subset_of_the_matrix;

// #Hard #Array #Greedy #Matrix #Bit_Manipulation
// #2023_09_22_Time_7_ms_(70.65%)_Space_57.2_MB_(5.43%)
// #2025_02_25_Time_2_ms_(100.00%)_Space_58.01_MB_(13.79%)

import java.util.ArrayList;
import java.util.HashMap;
import java.util.Arrays;
import java.util.List;
import java.util.Map;

public class Solution {
private int[] arr = new int[32];

public List<Integer> goodSubsetofBinaryMatrix(int[][] grid) {
int m = grid.length;
int n = grid[0].length;
if (m == 1 && sumArray(grid[0]) == 0) {
return List.of(0);
}
Map<Integer, Integer> pos = new HashMap<>();
for (int i = 0; i < m; i++) {
for (int mask = 0; mask < (1 << n); mask++) {
boolean valid = true;
for (int j = 0; j < n; j++) {
if ((mask & (1 << j)) != 0 && grid[i][j] + 1 > 1) {
valid = false;
break;
}
}
if (valid && pos.containsKey(mask)) {
return List.of(pos.get(mask), i);
}
List<Integer> list = new ArrayList<>();
int n = grid.length;
Arrays.fill(arr, -1);
for (int i = 0; i < n; ++i) {
int j = get(grid[i]);
if (j == 0) {
list.add(i);
return list;
}
if (arr[j] != -1) {
list.add(arr[j]);
list.add(i);
return list;
}
int curr = 0;
for (int j = 0; j < n; j++) {
if (grid[i][j] == 1) {
curr = curr | (1 << j);
for (int k = 0; k < 32; ++k) {
if ((k & j) == 0) {
arr[k] = i;
}
}
pos.put(curr, i);
}
return new ArrayList<>();
return list;
}

private int sumArray(int[] arr) {
int sum = 0;
for (int num : arr) {
sum += num;
private int get(int[] nums) {
int n = nums.length;
int rs = 0;
for (int i = 0; i < n; ++i) {
if (nums[i] == 1) {
rs = (rs | (1 << i));
}
}
return sum;
return rs;
}
}
Original file line number Diff line number Diff line change
Expand Up @@ -10,13 +10,11 @@ public int paintWalls(int[] cost, int[] time) {
int[] dp = new int[n + 1];
Arrays.fill(dp, (int) 1e9);
dp[0] = 0;

for (int i = 0; i < n; ++i) {
for (int j = n; j > 0; --j) {
dp[j] = Math.min(dp[j], dp[Math.max(j - time[i] - 1, 0)] + cost[i]);
}
}

return dp[n];
}
}