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[이지영] 16주차 81302번 과제 제출합니다. #112
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,37 @@ | ||
| answer = [] | ||
| #23점 코드입니다. | ||
| def dfs(m,x,y,flag,visitt): | ||
| if flag<=2 and m[y][x] != '1' and m[y][x] != 'X': | ||
| flag += 1 | ||
| visitt.append(m[y][x]) | ||
| m[y][x] = '1' #방문 표시 | ||
| dfs(m,x+1,y,flag,visitt) | ||
| dfs(m,x-1,y,flag,visitt) | ||
| dfs(m,x,y+1,flag,visitt) | ||
| dfs(m,x,y-1,flag,visitt) | ||
| dfs(m,x+1,y+1,flag,visitt) | ||
| dfs(m,x-1,y-1,flag,visitt) | ||
| dfs(m,x-1,y+1,flag,visitt) | ||
| dfs(m,x+1,y-1,flag,visitt) | ||
| return visitt | ||
|
|
||
|
|
||
| def solution(places): | ||
| for m in places: | ||
| cnt = 1 | ||
| m = list(map(list,m)) | ||
| for i,m_x in enumerate(m): | ||
| for ii,m_y in enumerate(m_x) : | ||
| if m_y == 'P': | ||
| if i<0 or i>4 or ii<0 or ii>4: | ||
| break | ||
| else: | ||
| m_c = m.copy() | ||
| visittt = dfs(m_c,i,ii,0,[]) | ||
| if visittt.count('P')>=2: | ||
| cnt = 0 | ||
| break | ||
| if cnt == 0: | ||
| break | ||
| answer.append(cnt) | ||
| return answer | ||
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PXPXP ...일 때 정답은 1인데 0을 리턴합니다.
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감사합니다!